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# Impulse M2 question? watch

1. A collision occurs between particles A and B which are moving in opposite directions in the same straight line. The impulse of each particle in the collision is 2 Ns.
a) Given that A has mass 0.4kg and initial velocity 3m/s, calculate the final velocity.
b) Given that the velocity of B changes by 2.5m/s, calculate the mass of B.
c) Deduce the maximum value for the initial speed of B.
2. a) impulse = mass(final velocity - initial velocity) so rearrange for final velocity and sub the numbers in
b) use the same equation because final velocity - initial velocity is the change in velocity. it rearranges to give mass = impulse/change in velocity
3. (Original post by maryamk97)
a) impulse = mass(final velocity - initial velocity) so rearrange for final velocity and sub the numbers in
b) use the same equation because final velocity - initial velocity is the change in velocity. it rearranges to give mass = impulse/change in velocity
Thanks! C is a b*@!h, using the impulse equation just leads to 0=0 and i'm not sure if you can use conservation of momentum here
4. I'm stuck on this one too and i can't do it. I keep getting different answers

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Updated: February 18, 2016
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