Turn on thread page Beta
    • Thread Starter
    Offline

    2
    ReputationRep:
    I don't understand how to even do question 1 of this exercise, or how the examples work. For example 1, the question (a) is work out the value, in radians of arcsin(-root2/2). The example seems to just state without explanation that this is equal to pi/4. I don't really see how it helps to understand how to do the questions in 6E.

    Without using a calculator, work out the values ,in terms of pi, of:

    Arccos0
    Arcsin1
    Arctan-1
    Arcsin-1/2

    And so on... Can anybody explain how to work these out?
    Offline

    22
    ReputationRep:
    (Original post by jamb97)
    I don't understand how to even do question 1 of this exercise, or how the examples work. For example 1, the question (a) is work out the value, in radians of arcsin(-root2/2). The example seems to just state without explanation that this is equal to pi/4. I don't really see how it helps to understand how to do the questions in 6E.

    Without using a calculator, work out the values ,in terms of pi, of:

    Arccos0
    Arcsin1
    Arctan-1
    Arcsin-1/2

    And so on... Can anybody explain how to work these out?
    You'll need to memorise the values of trigonometric functions with argument 0, 30, 45, 60, and 90 degrees.

    Once you know those, the questions are asking you:

    arccos 0 - what number do you need to take the cos of to give you 0? Hmm, well I know that cos 90 = 0 so arccos 0 = 90.
    Offline

    18
    Yeah, as Zacken said, you're expected to memorise those values

    But... As my teacher keeps reminding us, due to advancements in technology and the acceptable use of a calculator, we don't really have to memorise them (unless you want to do maths at a higher level) yay to calculators right?

    As a side, a thing I like to do is write arcsin as sin-1 etc because I'm used to seeing it like that, might help a bit idk!
    • Thread Starter
    Offline

    2
    ReputationRep:
    (Original post by Zacken)
    You'll need to memorise the values of trigonometric functions with argument 0, 30, 45, 60, and 90 degrees.

    Once you know those, the questions are asking you:

    arccos 0 - what number do you need to take the cos of to give you 0? Hmm, well I know that cos 90 = 0 so arccos 0 = 90.
    That has made things clear. Thank you
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: January 31, 2016
Poll
Favourite type of bread
Useful resources

Make your revision easier

Maths

Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

Equations

How to use LaTex

Writing equations the easy way

Student revising

Study habits of A* students

Top tips from students who have already aced their exams

Study Planner

Create your own Study Planner

Never miss a deadline again

Polling station sign

Thinking about a maths degree?

Chat with other maths applicants

Can you help? Study help unanswered threads

Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.