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Using bezouts lemma for a proof Watch

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    Hi, I'm struggling on where to go with this proof..
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    Would it be sufficient and correct to prove ab is a factor of m and a factor of m divided by a factor of m is a factor of m?

    Thanks for any help!

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    (Original post by Substitution)
    Hi, I'm struggling on where to go with this proof..
    Name:  image.jpg
Views: 51
Size:  443.2 KB
    Would it be sufficient and correct to prove ab is a factor of m and a factor of m divided by a factor of m is a factor of m?

    Thanks for any help!

    Attachment 499423499427
    Nope, unfortunately, that's not true, eg, a=6, b=9, m=18. Use Bezout's to express hcf(a,b) as ac+bd for some integers c and d. Now, let ia=m and jb=m, then sub these values in to your m/l expression.
 
 
 
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