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# Modulus Function Question watch

1. Don't understand the question ☹️
(Ignore bottom question).
2. (Original post by TSRforum)

Don't understand the question ☹️
(Ignore bottom question).
A different example which will give you a hint:

x^2 is always positive so | x^2 | is identical to x^2 since taking the absolute value has no effect for a positive number.

Now what can you say about 2x - 1 when x > 0.5 ?
3. (Original post by notnek)
A different example which will give you a hint:

x^2 is always positive so | x^2 | is identical to x^2 since taking the absolute value has no effect for a positive number.

Now what can you say about 2x - 1 when x > 0.5 ?
Y is greater than zero?

Still don't understand ..

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4. (Original post by TSRforum)
Y is greater than zero?

Still don't understand ..

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When x > 0.5, 2x - 1 is always positive (check this).

So | 2x - 1 | is the same as 2x - 1.

S y = x + | 2x - 1 | is the same as _____________
5. (Original post by notnek)
When x > 0.5, 2x - 1 is always positive (check this).

So | 2x - 1 | is the same as 2x - 1.

S y = x + | 2x - 1 | is the same as _____________
3x-1?

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6. Correct.
7. When x>1/2, |2x-1|=2x-1
When x<1/2, |2x-1|=1-2x
8. (Original post by B_9710)
When x>1/2, |2x-1|=2x-1
When x<1/2, |2x-1|=1-2x

Find the solution of eq. |x-3| + |x+3| = 6

(Requires sketching y=|x|, y=|x-3| and y= |x-3| + |x+3|)

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9. (Original post by TSRforum)

Find the solution of eq. |x-3| + |x+3| = 6

(Requires sketching y=|x|, y=|x-3| and y= |x-3| + |x+3|)

Posted from TSR Mobile
Split it up. Consider what happens to the modulus functions when x>3, when x<-3, when -3<x<3.
10. (Original post by B_9710)
Split it up. Consider what happens to the modulus functions when x>3, when x<-3, when -3<x<3.
Don't understand what you mean...

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11. (Original post by TSRforum)
Don't understand what you mean...

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Also how would I go about sketching y= |x-3| + |x+3|?

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12. (Original post by TSRforum)

Don't understand the question ☹️
(Ignore bottom question).
|x|= x for x>=0 pr -x for x<0
When is 2x-1>=0 or <0?

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13. (Original post by TSRforum)
Also how would I go about sketching y= |x-3| + |x+3|?

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Split between regions x>3, x<-3 and -3<x<3

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14. (Original post by physicsmaths)
|x|= x for x>=0 pr -x for x<0
When is 2x-1>=0 or <0?

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Need help with the second question I posted

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15. (Original post by physicsmaths)
Split between regions x>3, x<-3 and -3<x<3

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Don't understand...

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16. (Original post by TSRforum)
Don't understand...

Posted from TSR Mobile
When x>3, |x-3|=x-3 and |x+3|=x+3.
Use this logic to show what happens to each of the modulus functions in the 3 regions I said earlier.
Make sense or still not sure?
17. (Original post by B_9710)
When x>3, |x-3|=x-3 and |x+3|=x+3.
Use this logic to show what happens to each of the modulus functions in the 3 regions I said earlier.
Make sense or still not sure?
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Updated: February 5, 2016
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