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Why is the answer negative? Calculating gradient?!



I got the answer right, but it should have been negative? -10750 +/- 250
How's that?
(edited 8 years ago)
Original post by Adorable98


I got the answer right, but it should have been negative? -10750 +/- 250
How's that?


Activation energy can NEVER be negative ...
Reply 2
Original post by charco
Activation energy can NEVER be negative ...

Oops!
I meant to say "gradient" not activation energy.
(edited 8 years ago)
Because the difference is actually the end number - the start number therefore you will get about -5 for your change in y
Reply 4
Original post by Adorable98

Spoiler



Shoulda started with your Y-coordinates the other way round (-1.709 - 3.122 = -4.831) because otherwise you're doing -(dy/dx)
if the coordinates are (X1,Y1) and (X2,Y2) then you find the differences between the Ys and then divide it by the difference between the X.
Looking at the graph u can already tell it's negative as its a slope towards the right.

For you it's: (0.0028,3.122) and (-1.7,0.00328) so it's (3.122--1.7) ÷ (0.0028 - 0.00328)
Reply 6
Using m = (y2 - y1) / (x2 - x1) you should get in the habit of explicitly writing down the two coordinates you're using and labelling them (x1,y1) and (x2,y2) before substituting.
Reply 7
Original post by abbeymaysykes
Because the difference is actually the end number - the start number therefore you will get about -5 for your change in y


Original post by Alexion
Shoulda started with your Y-coordinates the other way round (-1.709 - 3.122 = -4.831) because otherwise you're doing -(dy/dx)


Original post by Back off Mods
if the coordinates are (X1,Y1) and (X2,Y2) then you find the differences between the Ys and then divide it by the difference between the X.
Looking at the graph u can already tell it's negative as its a slope towards the right.

For you it's: (0.0028,3.122) and (-1.7,0.00328) so it's (3.122--1.7) ÷ (0.0028 - 0.00328)


Original post by offhegoes
Using m = (y2 - y1) / (x2 - x1) you should get in the habit of explicitly writing down the two coordinates you're using and labelling them (x1,y1) and (x2,y2) before substituting.

I see thanks everyone!!

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