6d jan 02

Ho : p=0.4 H1 : p>0.4

n=10 p=0.4 X-B(10,0.4)

P(X>=8) = 1- P(X<=7)
= 1- 0.9877 (FROM TABLES)
= 0.0123
which is less than 5% so u reject Ho

Reply 5

zxcvbnm

5d
it is a rectangular distribution form 180 to 200 ml and height 0.05

so it look like this 0.05 ---------------------------
180 x 200

suppose x is in the middle as shown in diagram above
then (200-x)(0.05)=2(x-180)(0.05)
solve this to get x= 186.67 (approx)

5e

this means that 1/3 of cups have less than 0r equal to 186.67 ml

Reply 6

babylon

OP

zxcvbnm

5d
it is a rectangular distribution form 180 to 200 ml and height 0.05

so it look like this 0.05 ---------------------------
180 x 200

suppose x is in the middle as shown in diagram above
then (200-x)(0.05)=2(x-180)(0.05)
solve this to get x= 186.67 (approx)

5e

this means that 1/3 of cups have less than 0r equal to 186.67 ml

hmm thx but don't understand it, but its no big deal, i doubt it'll come up and if it does its only 5 marks.....
i've forgotten stuff bout skewness..........if mean<median<mode....is that negative skew or positive?

Reply 7

zxcvbnm

7d

from 7c u know that F(x)=x^3 + 3X^2 + 3X +1
so
P(-0.3<X<0.3)= F(0.3)-F(-0.3)
= 1 - 0.343 = 0.657

Note that F(0.3) is 1 coz the formuls for F(x) is valid from 0 to -1 and for all values above 0 the F(x)=1

i hope this will help u ....by the way what is ajmals website can u plz give me the adress :smile:

Reply 8

zxcvbnm

the diagram is crappy that y i might have problems but try to make ur own on a paper ... u will understand it :smile:

Reply 9

babylon

OP

zxcvbnm

7d

from 7c u know that F(x)=x^3 + 3X^2 + 3X +1
so
P(-0.3<X<0.3)= F(0.3)-F(-0.3)
= 1 - 0.343 = 0.657

Note that F(0.3) is 1 coz the formuls for F(x) is valid from 0 to -1 and for all values above 0 the F(x)=1

i hope this will help u ....by the way what is ajmals website can u plz give me the adress :smile:

thx so much, i get the idea of it...but for 7c i got F(x)= x^3 + 3x^2 + 3x.....where did u get +1 from?
www.ajimal.com

Reply 10

zxcvbnm

i think u have applied wrong limits.. the limits are x and -1 NOT x and 0

Reply 11

babylon

OP

zxcvbnm

i think u have applied wrong limits.. the limits are x and -1 NOT x and 0

oh dammit, how am i supposed to know?! i just assumed limits were 0 and -1.......why r u supposed to use x? and why is it x and -1?

Reply 12

babylon

OP

wonkey

oh dammit, how am i supposed to know?! i just assumed limits were 0 and -1.......why r u supposed to use x? and why is it x and -1?

ok, i understand y its X and -1 now.........

Reply 13

zxcvbnm

remember one rule that the limits for F(x) for every case are
- infinity to +infinity

but u ignore the areas that we are not interseted in.

basically the easy rule is always apply the limits as x and (the lowest number)

S2 jan 02

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