# Force on magnetic field and velocity

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When the force on a charge moving in a circular motion in a magnetic field is doubled, what is the effect on its velocity? I thought since Force = Bqv, the force is doubled but turns out that I am wrong because the Force is also mv^2/r and it is quadrupled. So, how do I know which equation to use?

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When the force on a charge moving in a circular motion in a magnetic field is doubled, what is the effect on its velocity? I thought since Force = Bqv, the force is doubled but turns out that I am wrong because the Force is also mv^2/r and it is quadrupled. So, how do I know which equation to use?

**anillatoo**)When the force on a charge moving in a circular motion in a magnetic field is doubled, what is the effect on its velocity? I thought since Force = Bqv, the force is doubled but turns out that I am wrong because the Force is also mv^2/r and it is quadrupled. So, how do I know which equation to use?

I think you're getting getting confused between velocity & force. By using the centripetal force equation;

If the force is doubled, then the velocity will be doubled (provided radius and mass remain constant), see photo attachment

If the velocity is doubled, then the force will be quadrupled (provided radius and mass remain constant), since the velocity is squared (2^2 = 4)

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(Original post by

Hi, is this an exert from a question, and does the mark scheme give an answer of velocity becomes 4x? I make it that velocity is doubled, when force is doubled, for both equations

I think you're getting getting confused between velocity & force. By using the centripetal force equation;

If the force is doubled, then the velocity will be doubled (provided radius and mass remain constant), see photo attachment

If the velocity is doubled, then the force will be quadrupled (provided radius and mass remain constant), since the velocity is squared (2^2 = 4)

**JohnnyDavidson**)Hi, is this an exert from a question, and does the mark scheme give an answer of velocity becomes 4x? I make it that velocity is doubled, when force is doubled, for both equations

I think you're getting getting confused between velocity & force. By using the centripetal force equation;

If the force is doubled, then the velocity will be doubled (provided radius and mass remain constant), see photo attachment

If the velocity is doubled, then the force will be quadrupled (provided radius and mass remain constant), since the velocity is squared (2^2 = 4)

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**JohnnyDavidson**)

Hi, is this an exert from a question, and does the mark scheme give an answer of velocity becomes 4x? I make it that velocity is doubled, when force is doubled, for both equations

I think you're getting getting confused between velocity & force. By using the centripetal force equation;

If the force is doubled, then the velocity will be doubled (provided radius and mass remain constant), see photo attachment

If the velocity is doubled, then the force will be quadrupled (provided radius and mass remain constant), since the velocity is squared (2^2 = 4)

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Sorry, yea, I got confused. So, when do I use F = Bqv?

**anillatoo**)Sorry, yea, I got confused. So, when do I use F = Bqv?

if force doubled (times both side by 2): 2F = 2bqv

Therefore, provided b and q remain constant, velocity will be doubled.

(Original post by

Centripetal force does not have an equation..... mv^2/r is not centripetal force it is the resultant of the forces, teachers who teach it as centripetal will cost students marks in the exams.

**Konanabanana**)Centripetal force does not have an equation..... mv^2/r is not centripetal force it is the resultant of the forces, teachers who teach it as centripetal will cost students marks in the exams.

Centripetal force is the resultant force, which can be applied whenever an object is in uniform circular motion. In this case the only force acting on the object/charge is the magnetic force, so this is therefore the resultant force, which is the centripetal force.

So yes centripetal force is never a separate force, it is always "provided" by something else (in this case only the magnetic force, if there were more forces, it would be the resultant force of those).

So if the object is in uniform circular motion, the velocity (magnitude of), radius of orbit, and mass, can be found using the equation: F = (mv^2) / r, taking F as the resultant force.

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You could have used either here, both will give velocity doubled.F = bqv

if force doubled (times both side by 2): 2F = 2bqv

Therefore, provided b and q remain constant, velocity will be doubled.

Yes that is true, perhaps I didn't quite explain it fully, though I am only an a2 student myself so not sure exactly on the definition lol.

Centripetal force is the resultant force, which can be applied whenever an object is in uniform circular motion. In this case the only force acting on the object/charge is the magnetic force, so this is therefore the resultant force, which is the centripetal force.

So yes centripetal force is never a separate force, it is always "provided" by something else (in this case only the magnetic force, if there were more forces, it would be the resultant force of those).

So if the object is in uniform circular motion, the velocity (magnitude of), radius of orbit, and mass, can be found using the equation: F = (mv^2) / r, taking F as the resultant force.

**JohnnyDavidson**)You could have used either here, both will give velocity doubled.F = bqv

if force doubled (times both side by 2): 2F = 2bqv

Therefore, provided b and q remain constant, velocity will be doubled.

Yes that is true, perhaps I didn't quite explain it fully, though I am only an a2 student myself so not sure exactly on the definition lol.

Centripetal force is the resultant force, which can be applied whenever an object is in uniform circular motion. In this case the only force acting on the object/charge is the magnetic force, so this is therefore the resultant force, which is the centripetal force.

So yes centripetal force is never a separate force, it is always "provided" by something else (in this case only the magnetic force, if there were more forces, it would be the resultant force of those).

So if the object is in uniform circular motion, the velocity (magnitude of), radius of orbit, and mass, can be found using the equation: F = (mv^2) / r, taking F as the resultant force.

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Forces always will have components, meaning there is always more than one force acting on them. Also centripetal force is not a force.

**Konanabanana**)Forces always will have components, meaning there is always more than one force acting on them. Also centripetal force is not a force.

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How is it not a Force?! Anyway, I am still confused about the effect of Force on velocity in a magnetic field; on one hand it is proportional (F=Bqv) and on another hand, it is proportional to the square(F= mv^2/r)

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Forces always will have components, meaning

**Konanabanana**)Forces always will have components, meaning

**there is always more than one force acting on them**. Also centripetal force is not a force.
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**anillatoo**)

When the force on a charge moving in a circular motion in a magnetic field is doubled, what is the effect on its velocity? I thought since Force = Bqv, the force is doubled but turns out that I am wrong because the Force is also mv^2/r and it is quadrupled. So, how do I know which equation to use?

**as a result of**a change in one or more of the variables , but

**not**vice versa.

On the other hand, the equation *could* express the effect of velocity of the charged particle in the magnetic field if the magnetic force was to be doubled (assuming the mass and radius of the orbit remain constant). Hence,

, where C is a constant. Then we have,

. Rearranging for we get,

.

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(Original post by

You cannot really answer the question until a few things are assumed. However, since the question demands the effect of velocity when the magnetic force is doubled, we need to assume that magnetic field strength, charge and radius of orbit are remained constant. Therefore, you cannot use the magnetic force equation, , because the force in this equation is the dependent variable, meaning the force on a charge particle varies

On the other hand, the equation *could* express the effect of velocity of the charged particle in the magnetic field if the magnetic force was to be doubled (assuming the mass and radius of the orbit remain constant). Hence,

, where C is a constant. Then we have,

. Rearranging for we get,

.

**Absent Agent**)You cannot really answer the question until a few things are assumed. However, since the question demands the effect of velocity when the magnetic force is doubled, we need to assume that magnetic field strength, charge and radius of orbit are remained constant. Therefore, you cannot use the magnetic force equation, , because the force in this equation is the dependent variable, meaning the force on a charge particle varies

**as a result of**a change in one or more of the variables , but**not**vice versa.On the other hand, the equation *could* express the effect of velocity of the charged particle in the magnetic field if the magnetic force was to be doubled (assuming the mass and radius of the orbit remain constant). Hence,

, where C is a constant. Then we have,

. Rearranging for we get,

.

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#12

There seems to be some confusion between a few things:

Firstly, increasing the magnetic field will increase the force on the electron. It will not however, change it's speed as magnetic forces do no work. What it will do is cause it to move in a tighter circle.

Second - the term centripetal force refers to any force causing circular motion. It is not an 'extra' force you get when moving in a circle. It just happens that in order to turn, you need to apply a force.

Thirdly - you can't use equations backwards! If you double the velocity of the particle, then the force will double (again, will go in a smaller circle) but the reverse is not true because you can't just arbitrarily "double the force" - what you can do is double the field. Same with v^2/r - if you increase v you don't have to increase the force as you might simply stop going in a circle (not in this case though).

Firstly, increasing the magnetic field will increase the force on the electron. It will not however, change it's speed as magnetic forces do no work. What it will do is cause it to move in a tighter circle.

Second - the term centripetal force refers to any force causing circular motion. It is not an 'extra' force you get when moving in a circle. It just happens that in order to turn, you need to apply a force.

Thirdly - you can't use equations backwards! If you double the velocity of the particle, then the force will double (again, will go in a smaller circle) but the reverse is not true because you can't just arbitrarily "double the force" - what you can do is double the field. Same with v^2/r - if you increase v you don't have to increase the force as you might simply stop going in a circle (not in this case though).

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#13

**Konanabanana**)

Forces always will have components, meaning there is always more than one force acting on them. Also centripetal force is not a force.

*any*force that keeps an object in circular motion, whether its cause is tension or friction (or something else?). The centrifugal force is the one that is fictitious and comes about depending on reference frame.

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