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    Can someone please help me solve this?

    Q) Eletrons in a particle accelerator are moving at 8.0x10^5ms-1 when they enter a tube where they accelerated to 6.5x10^6 ms-1
    a)What is their acceleration in the tube?
    b)What is the length of the tube?

    Q)A high speed train can slow down smoothly from a speed of 190kmh^-1 to rest within a distance of 1500m.
    a)What is the average speed of the train, in, ms^-1, as it slows down?

    These kind of questions really annoy me
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    (Original post by CookieHero)
    Can someone please help me solve this?

    Q) Eletrons in a particle accelerator are moving at 8.0x10^5ms-1 when they enter a tube where they accelerated to 6.5x10^6 ms-1
    a)What is their acceleration in the tube?
    b)What is the length of the tube?

    Q)A high speed train can slow down smoothly from a speed of 190kmh^-1 to rest within a distance of 1500m.
    a)What is the average speed of the train, in, ms^-1, as it slows down?

    These kind of questions really annoy me
    Appears to be some information missing in the first question...
    is it related to Q 1.26 here http://www.hatchend.harrow.sch.uk/_f...A8547A142C.pdf
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    (Original post by Joinedup)
    Appears to be some information missing in the first question...
    is it related to Q 1.26 here http://www.hatchend.harrow.sch.uk/_f...A8547A142C.pdf
    I do have the book and yes it is Q 1.26. In the back of the book it says the answer is 9.0 x 10^12 ms^-2 for quesiton 1.26a

    I'm guessing there are actually missing information in the questions.
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    (Original post by CookieHero)
    Can someone please help me solve this?

    Q) Eletrons in a particle accelerator are moving at 8.0x10^5ms-1 when they enter a tube where they accelerated to 6.5x10^6 ms-1
    a)What is their acceleration in the tube?
    b)What is the length of the tube?

    Q)A high speed train can slow down smoothly from a speed of 190kmh^-1 to rest within a distance of 1500m.
    a)What is the average speed of the train, in, ms^-1, as it slows down?

    These kind of questions really annoy me
    did it say how long the electrons were in the tube for ?
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    (Original post by the bear)
    did it say how long the electrons were in the tube for ?
    nope D:
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    (Original post by CookieHero)
    nope D:
    perhaps they mentioned the kinetic energy of the electrons ?
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    (Original post by CookieHero)
    Can someone please help me solve this?

    Q) Eletrons in a particle accelerator are moving at 8.0x10^5ms-1 when they enter a tube where they accelerated to 6.5x10^6 ms-1
    a)What is their acceleration in the tube?
    b)What is the length of the tube?

    Q)A high speed train can slow down smoothly from a speed of 190kmh^-1 to rest within a distance of 1500m.
    a)What is the average speed of the train, in, ms^-1, as it slows down?

    These kind of questions really annoy me
    Q1a) a = v - u (final velocity minus initial velocity)

    Q1b) using v = u + at, you can solve for time.

    then we can use s = ut +1/2 at^2 to get the length of the tube.

    Q2a) Average speed = (v + u)/2 or the two velocities added together and divided by two.
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    (Original post by the bear)
    did it say how long the electrons were in the tube for ?
    (Original post by the bear)
    perhaps they mentioned the kinetic energy of the electrons ?

    Please see my above post.
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    (Original post by CookieHero)
    nope D:
    Using just the info you provided, it is not possible to solve the first question but using the info in the link provided by one of the other posters it should be easy as you're given the time, initial and final velocity
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    (Original post by Kyx)
    Q1a) a = v - u (final velocity minus initial velocity)

    Q1b) using v = u + at, you can solve for time.

    then we can use s = ut +1/2 at^2 to get the length of the tube.

    Q2a) Average speed = (v + u)/2 or the two velocities added together and divided by two.
    acceleration doesnt = v-u

    v-u just gives the change in velocity

    a= (v-u)/t
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    (Original post by Kyx)
    Please see my above post.
    as i suspected there was some extra information to enable the use of SUVAT equations.
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    (Original post by madmadmax321)
    acceleration doesnt = v-u

    v-u just gives the change in velocity

    a= (v-u)/t
    Of course!
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    I get it now thanks
    • Aston Villa FC Supporter
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    (Original post by CookieHero)
    I get it now thanks
    What was it?
    • Thread Starter
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    (Original post by Kyx)
    What was it?
    wut was what? :?
    • Aston Villa FC Supporter
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    (Original post by CookieHero)
    wut was what? :?
    The answer?
 
 
 
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