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A pupil is beaten badly by this G.P. Watch

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    One of my cocky students (wants to do medicine because maths is too easy) asked to give him my "best shot" because there was no question on G.P.s he could not do...

    So I made this question, live at his lesson, and he was beaten really badly.
    Non Calculator As Well.

    Name:  GP.jpg
Views: 517
Size:  27.0 KB

    Any thoughts?
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    Should have given him this:
    U1 + U2 = 150
    U2 + U4 = -75

    Find a and r


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    Help me in the C4 d.e. thread please 🙃


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    (Original post by TSRforum)
    Should have given him this:
    U1 + U2 = 150
    U2 + U4 = -75

    Find a and r


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    he managed this type ...
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    The title of the thread led me to believe a kid got beaten up by his doctor...
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    Also I'm pretty sure doing maths is harder than medicine, is it?


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    (Original post by TSRforum)
    Also I'm pretty sure doing maths is harder than medicine, is it?


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    I think it might be ...
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    (Original post by TeeEm)
    One of my cocky students (wants to do medicine because maths is too easy) asked to give him my "best shot" because there was no question on G.P.s he could not do...

    So I made this question, live at his lesson, and he was beaten really badly.
    Non Calculator As Well.

    Name:  GP.jpg
Views: 517
Size:  27.0 KB

    Any thoughts?
    all his base are yours

    :nyan:
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    (Original post by TeeEm)
    One of my cocky students (wants to do medicine because maths is too easy) asked to give him my "best shot" because there was no question on G.P.s he could not do...

    So I made this question, live at his lesson, and he was beaten really badly.
    Non Calculator As Well.

    Name:  GP.jpg
Views: 517
Size:  27.0 KB

    Any thoughts?
    \displaystyle \frac{u_1}{1-r} = 4u_1 r (sum to infinity is four times as big as second term), hence, since u_1 \neq 0:

    \displaystyle 4r^2 - 4r + 1 = 0 \iff r = \frac{1}{2}, now we know that the sum to infinity is 192, so:

    \displaystyle 2u_1 = 192 \iff u_1 = 96. So, the sum to k terms is:

    \displaystyle \frac{96(1-2^{-k})}{2^{-1}} = 180 \iff 2^{-k} = 2^{-4} \iff k = 4
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    (Original post by the bear)
    all his base are yours

    :nyan:
    had to be done...
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    (Original post by Zacken)
    \displaystyle \frac{u_1}{1-r} = 4ar (sum to infinity is four times as big as second term), hence, since a \neq 0:

    \displaystyle 4r^2 - 4r + 1 = 0 \iff r = \frac{1}{2}, now we know that the sum to infinity is 192, so:

    \displaystyle 2u_1 = 192 \iff u_1 = 96. So, the sum to k terms is:

    \displaystyle \frac{96(1-2^{-k})}{2^{-1}} = 180 \iff 2^{-k} = 2^{-4} \iff k = 4
    you win the "Brucie" bonus ...!!
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    (Original post by TeeEm)
    you win the "Brucie" bonus ...!!
    Is that correct? Yay. Can you see my face yet?
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    (Original post by Zacken)
    Is that correct? Yay. Can you see my face yet?
    I cannot see your face ... Don't you have a better picture?!
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    (Original post by TeeEm)
    I cannot see your face ... Don't you have a better picture?!
    Blame monobrow girl: tinkerbella~
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    (Original post by Zacken)
    Blame monobrow girl: tinkerbella~
    has she dented your confidence?
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    (Original post by TeeEm)
    has she dented your confidence?
    I have a great picture of his face if you want to see it :yep:
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    (Original post by tinkerbella~)
    I have a great picture of his face if you want to see it :yep:
    I would love to
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    (Original post by Zacken)
    X
    Yours looks much neater but hey - I've never attempted one of TeeEm's before so let me have my moment
    Spoiler:
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    (Original post by Student403)
    ...
    Nice work!
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    (Original post by TeeEm)
    I would love to
    He sent me nasty threats and I'm too scared.
    Btw I thought this thread was going to be some big NHS scandal but it's just maths, the disappointment hurts.
 
 
 
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