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Rate determining Step questions - F325- Chemistry watch

    • Thread Starter

    This question belongs to the unifying concepts January 2006. The rate equation is Rate = K {H+}{Propanone}

    Suggest the equations for a possible two step reaction mechanism.
    I know the answer, for the slow step/ rate determining step, the propanone reacts with the H+ proton. I'm just wondering what kind of reaction the propanone and H+ undergo

    Bear in mind this is an old spec question, but this is in line with similar questions that is coming up in the recent F325 papers. Any advice, on what reaction propanone and H+ undergo would be appreciated.
    •  Official Rep

     Official Rep
    Sorry you've not had any responses about this.

    Why not try posting in a specific subject forum- you might have more luck there.

    Here's a link to our subject forum which should help get you more responses.

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