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    I don't understand how you get to the answer in the following question/

    Each day on the way to work, a commuter encounters a similar traffic jam. the length of time, in 10 min univts, spent waiting in the traffic jam is modelled by the random variable T with the cumulative frequency distribution:

    F(t) = 0 t < 0
    F(t) = 1/16[t²(3t² - 16t + 24)] 0≤t≤2
    F(t) = 1 t>2

    Given that he has already wated for 12 mins, find the probability that he will have to wait another 3 mins.


    At first I found f(1.5) but quickly realised that was so not the way to do it :rolleyes: I know they want P(1.5|1.2) but how do I find out P(1.5 n 1.2)?
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    sorry mods, kept getting a 'server busy message' so posted this twice. Can someone delete this?
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    (Original post by Mysticmin)

    At first I found f(1.5) but quickly realised that was so not the way to do it :rolleyes: I know they want P(1.5|1.2) but how do I find out P(1.5 n 1.2)?
    We have to know that 'given that' stuff from S1? :eek:
 
 
 
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Updated: June 22, 2004
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