# help P3Watch

This discussion is closed.
14 years ago
#21
(Original post by TheWolf)
ahh cool i think you meant quotient for the latter - but yea thanks!
Yeah, I did. Edited it now.
0
14 years ago
#22
(Original post by mik1a)
Express as partial fractions:

(x^2 + 1)/(x^2 - 1)

with these ones find a way to make the change the bottom to the top

that sounds a bit confusing

ok
(x^2 - 1) + something = (x^2 + 1)

this one is quite easy, its 2

so the fraction is
[(x^2 - 1) + 2] / (x^2 - 1)

= 1 + 2/(x+1)(x-1)

which you can do as normal
0
14 years ago
#23
(Original post by kikzen)
with these ones find a way to make the change the bottom to the top

that sounds a bit confusing

ok
(x^2 - 1) + something = (x^2 + 1)

this one is quite easy, its 2

so the fraction is
[(x^2 - 1) + 2] / (x^2 - 1)

= 1 + 2/(x+1)(x-1)

which you can do as normal
I dont know if youve noticed but weve already done/explained this?
0
14 years ago
#24
(Original post by thenarbisbanned)
I dont know if youve noticed but weve already done/explained this?
whoops.

i thought about reading through to check if it had been suggested but then i thought.. hmm well if someones not posted it then it'd be good but if they have then at least i tried to do my bit ;p

(plus reading thru sounded like a bit too much work)
0
14 years ago
#25
express as partial fractions:

3/ (xÂ³) + 1
0
14 years ago
#26
(Original post by TheWolf)
express as partial fractions:

3/ (xÂ³) + 1

do u mean?

3/(xÂ³ +1)

OR

(3/xÂ³) + 1

??
0
14 years ago
#27
(Original post by integral_neo)
do u mean?

3/(xÂ³ +1)

OR

(3/xÂ³) + 1

??
ahh dont worry i know how to do it now, just have to factorize the bottom
0
14 years ago
#28
x^3 + 1 = (x+1)(x^2 - x + 1)
0
14 years ago
#29
(Original post by TheWolf)
ahh dont worry i know how to do it now, just have to factorize the bottom
0
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