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Help with a Q needed watch

1. Can someone help with this q?
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2. It's a little hard to read. Can you please take a clearer image closer in?
3. (Original post by Vorsah)
Can someone help with this q?
As above, preferably a screenshot!
4. Also please post what you've tried so far
5. I would imagine that if you integrate over the triangle you must get 1
6. (Original post by TeeEm)
I would imagine that if you integrate over the triangle you must get 1
Yh that's what I did and got C=1, but two of my friends got something else, which made me a little unsure.
7. (Original post by Vorsah)
Yh that's what I did and got C=1, but two of my friends got something else, which made me a little unsure.
8. (Original post by TeeEm)
Putting in (0,0) and (1,1) the function gives 0. Putting in (1,0) I get c*(1^6.98) =c

Then I integrated and got cx which must equal 1 then I put in the limits [0,1] and got c=1

Sorry if this doesn't look clear, but I'm on the train right now.
9. (Original post by Vorsah)
Putting in (0,0) and (1,1) the function gives 0. Putting in (1,0) I get c*(1^6.98) =c

Then I integrated and got cx which must equal 1 then I put in the limits [0,1] and got c=1

Sorry if this doesn't look clear, but I'm on the train right now.
I cannot check it right now either as I am in the middle of updating a website, but I will take a look when I finish.

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Updated: February 12, 2016
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