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    Help meh.

    Don't even know where to start :/

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    it is not really logarithm work...

    you get the same results with

    { P + Q } / { PQ }

    and

    { K2 - 1 } / { K - 1}
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    A denominator can go under each part of a numerator

    eg (3 + 2)/ 6 = 3/6 + 2/6

    Another hint: remember difference of 2 squares?
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    (Original post by the bear)
    it is not really logarithm work...

    you get the same results with

    { P + Q } / { PQ }

    and

    { K2 - 1 } / { K - 1}
    When I first attempted it I substituted x and y, but to no avail.

    I feel like I'm missing something -_-

    (Original post by maggiehodgson)
    A denominator can go under each part of a numerator

    eg (3 + 2)/ 6 = 3/6 + 2/6

    Another hint: remember difference of 2 squares?
    Didn't think of difference of two squares. I will try now

    Got the answer to th second one with difference of two squares :awesome: still don't know what to do for the first one though idk why
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    (Original post by IFoundWonderland)
    When I first attempted it I substituted x and y, but to no avail.

    I feel like I'm missing something -_-


    Didn't think of difference of two squares. I will try now

    Got the answer to th second one with difference of two squares :awesome: still don't know what to do for the first one though idk why
    splitting fractions.

    { V + W } / VW = V / VW + W / VW
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    (Original post by the bear)
    splitting fractions.

    { V + W } / VW = V / VW + W / VW
    Thank you :awesome:

    Why could I not see this before :getmecoat:
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    3/(3x6) = 1/6 The 3's cancel because you can create an equivalent fraction by dividing both numerator and denominator by 3.

    Has that helped?
 
 
 
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