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    I'm a little confused with part b) of Ex. G question 7:

    https://4cb73c3e1ece319eea2c1a4396b1...WJpMW8/CH4.pdf

    I'm not sure why the resultant force can be greater or smaller than the centripetal force. How can the CF have a different value to the resultant forces causing it?

    Thanks for any help!
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    Slipping in this instance refers to the particle rolling inwards towards the axis of rotation as opposed to remaining static at 3/5 a units away. Peace.
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    (Original post by WhiteGroupMaths)
    Slipping in this instance refers to the particle rolling inwards towards the axis of rotation as opposed to remaining static at 3/5 a units away. Peace.
    Thanks for your reply.

    I still don't understand how the centripetal force can have a different value to the resultant force caused by the friction and the tension
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    TeeEm
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    (Original post by PhyM23)
    Thanks for your reply.

    I still don't understand how the centripetal force can have a different value to the resultant force caused by the friction and the tension
    I don't understand what you're trying to say here, or how it relates to the question. Which resultant force are you thinking of?
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    (Original post by PhyM23)
    TeeEm
    what seems to be the problem?
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    (Original post by TeeEm)
    what seems to be the problem?
    I don't understand the logic behind the inequalities formed in the question. I understand the two possible scenarios with the friction acting towards or away from the centre, but I'm not sure how the tension+friction can be greater than the centripetal force, and how the tension-friction can be less than the centripetal force.
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    (Original post by PhyM23)
    I don't understand the logic behind the inequalities formed in the question. I understand the two possible scenarios with the friction acting towards or away from the centre, but I'm not sure how the tension+friction can be greater than the centripetal force, and how the tension-friction can be less than the centripetal force.
    there is no such thing as the centripetal force
    this is a term used by physicists

    post the question please
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    (Original post by TeeEm)
    there is no such thing as the centripetal force
    this is a term used by physicists

    post the question please
    It's 7b)
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    (Original post by PhyM23)
    It's 7b)
    I will do the question (with different numbers) and post a worked solution by late afternoon for you
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    (Original post by TeeEm)
    I will do the question (with different numbers) and post a worked solution by late afternoon for you
    Thank you very much
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    (Original post by PhyM23)
    Thank you very much
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    (Original post by TeeEm)
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    PRSOM

    Thanks, much appreciated. Is there a reason you took to be acting outwards? Is this just convention?
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    (Original post by PhyM23)
    PRSOM

    Thanks, much appreciated. Is there a reason you took to be acting outwards? Is this just convention?
    this is the direction of r increasing
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    (Original post by TeeEm)
    this is the direction of r increasing
    Ahh that makes sense
 
 
 
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