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    How would you answer this question?
    Do u start by writing every fragmentation equation possible?


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    It isn't asking about fragmentation, the Q asks about the molecular ion peak/s.

    Consider chloromethane. It will have two molecular ion peaks, one for CH335Cl and another due to CH337Cl.Now consider dichloromethane, there will be three peaks: one with 2x35Cl, two with 35Cl and 37Cl and one with 2x37Cl.

    Your molecule has 4xCl atoms. You do the math.

    Oooo 1500.
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    (Original post by Pigster)
    It isn't asking about fragmentation, the Q asks about the molecular ion peak/s.

    Consider chloromethane. It will have two molecular ion peaks, one for CH335Cl and another due to CH337Cl.Now consider dichloromethane, there will be three peaks: one with 2x35Cl, two with 35Cl and 37Cl and one with 2x37Cl.

    Your molecule has 4xCl atoms. You do the math.

    Oooo 1500.
    Oh so there will be 5 peaks in total. Also what does the most abundant molecular ion mean


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    35Cl makes up about 75% of all the Cl atoms.

    If you look at the MS of chloromethane, the peak at 50 (due to CH335Cl) is 3x the size of the peak at 52 (3:1 ratio = 75%:25%). The most abundant peak is simply the one that is most common, in that case, the peak at 50.

    Of the five peaks, which is most common?
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    (Original post by Pigster)
    35Cl makes up about 75% of all the Cl atoms.

    If you look at the MS of chloromethane, the peak at 50 (due to CH335Cl) is 3x the size of the peak at 52 (3:1 ratio = 75%:25%). The most abundant peak is simply the one that is most common, in that case, the peak at 50.

    Of the five peaks, which is most common?
    Oh okay so I think I got it. The most abundant peak is at 224? Correct?


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    I make it 320.
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    (Original post by Pigster)
    I make it 320.
    Ah thanks I got it


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