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Electrochemical cells watch

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    In the external circuit of this cell, the electrons flow from right to left. Suggest why they flow in this direction.
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    Could you post a picture of the cell? It is so I can give you a better answer.
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    (Original post by PLM98)
    Could you post a picture of the cell? It is so I can give you a better answer.
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    Okay so on the left cell we have standard conditions so E°=+0.34V. On the right the concentration of Cu2+ is lower, and hence the E value is less positive. Hence, the Cu2+ ions in the left half-cell are more easily reduced due to the higher Electrode Potential and so electrons in the copper electrode on the right half-cell will donate electrons to the left half-cell (becoming Cu2+), and Cu2+ ions on the left half cell will accept electrons from the right half-cell (becoming Cu(s)). Hope it helps!
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    That helped sooo much! Thank you.
    The explanation was perfect
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    I am glad I helped!! Let me know whenever you have any question!
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    (Original post by PLM98)
    I am glad I helped!! Let me know whenever you have any question!
    Okay will do, thank you again.
 
 
 
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