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    Hey can someone tell me please for question iv why the area is 4 instead of -4 even though the Y-co ordinate is -2?

    And can someone show me how to solve for x in this question:
    2x^-1/2=3/2x^1/2
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    (Original post by Msjaygaab)
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    Hey can someone tell me please for question iv why the area is 4 instead of -4 even though the Y-co ordinate is -2?

    And can someone show me how to solve for x in this question:
    2x^-1/2=3/2x^1/2
    Well, you can't have negative area, can you?

    For the second part, why don't you try multiplying both sides by sqrt(x)?
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    Oh yeah Thankyou
    And could you please show me how to do the second part im still unsure
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    Do you mean part b?


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    (Original post by Msjaygaab)


    And can someone show me how to solve for x in this question:
    2x^-1/2=3/2x^1/2
    \displaystyle \frac{2}{\sqrt{x}} = \frac{3\sqrt{x}}{2} \Rightarrow 2 = \frac{3x}{2} \Rightarrow \cdots
 
 
 
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