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# Help on calcus watch

1. Hey can someone tell me please for question iv why the area is 4 instead of -4 even though the Y-co ordinate is -2?

And can someone show me how to solve for x in this question:
2x^-1/2=3/2x^1/2
2. (Original post by Msjaygaab)

Hey can someone tell me please for question iv why the area is 4 instead of -4 even though the Y-co ordinate is -2?

And can someone show me how to solve for x in this question:
2x^-1/2=3/2x^1/2
Well, you can't have negative area, can you?

For the second part, why don't you try multiplying both sides by sqrt(x)?
3. Oh yeah Thankyou
And could you please show me how to do the second part im still unsure
4. Do you mean part b?

Posted from TSR Mobile
5. (Original post by Msjaygaab)

And can someone show me how to solve for x in this question:
2x^-1/2=3/2x^1/2

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