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# Trig Watch

1. In each of the following cases ABC (triangle) has ABC = and AB = 10 cm.

a) Calculate the least possible length that AC could be

How would you go about doing this
2. I think that the shortest distance to any line is a perpendicular.

Will that help?
3. Have you drawn a diagram to help you visualise the triangle?
4. (Original post by maggiehodgson)
I think that the shortest distance to any line is a perpendicular.

Will that help?

No, I don't understand
5. I know the answer is 5 cm when ACB is at a right angle...

but I want to know why
6. (Original post by Naruke)
No, I don't understand
Well, just draw two lines AB (10) and BX (quitet long) with a 30 degree angle between. Now look at the point A. You have to draw a line down to AX so that the line you draw is as short as possible. That line is a perpendicular. Were the line meets AX then that is the point C.

Give it a go and see if it helps.
7. i'm drawing a diagram....
8. here you go

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Updated: February 14, 2016
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