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c2 Logs

how does it go from:

log2(y/x)=4
y/x=2^4=16

I dont understand how it goes from log2 to 2^4?
Because the y over x has to be a number. Think of it like this log3x equals 2 theb what number does x have to be? X has to be 3^2
Original post by ameeis
how does it go from:

log2(y/x)=4
y/x=2^4=16

I dont understand how it goes from log2 to 2^4?


If loga(b)=clog_{a}(b) = c

Then b=ac b = a^{c}





So if log2xy=4log_{2}\frac{x}{y} = 4
Then using a=2,b=xy,c=4a = 2, b = \dfrac{x}{y}, c = 4
We can see that xy=24=16\dfrac{x}{y} = 2^4 = 16
Reply 3
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Zacken
22
Moved to maths.
Reply 4
Avatar for ameeis
ameeis
OP
Original post by edothero
If loga(b)=clog_{a}(b) = c

Then b=ac b = a^{c}





So if log2xy=4log_{2}\frac{x}{y} = 4
Then using a=2,b=xy,c=4a = 2, b = \dfrac{x}{y}, c = 4
We can see that xy=24=16\dfrac{x}{y} = 2^4 = 16


Thanks! It was a silly question as I realised as soon as I posted this! Thanks anyway

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