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    how does it go from:

    log2(y/x)=4
    y/x=2^4=16

    I dont understand how it goes from log2 to 2^4?
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    Because the y over x has to be a number. Think of it like this log3x equals 2 theb what number does x have to be? X has to be 3^2
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    (Original post by ameeis)
    how does it go from:

    log2(y/x)=4
    y/x=2^4=16

    I dont understand how it goes from log2 to 2^4?
    If log_{a}(b) = c

    Then  b = a^{c}





    So if log_{2}\frac{x}{y} = 4
    Then using a = 2, b = \dfrac{x}{y}, c = 4
    We can see that \dfrac{x}{y} = 2^4 = 16
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    Moved to maths.
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    (Original post by edothero)
    If log_{a}(b) = c

    Then  b = a^{c}





    So if log_{2}\frac{x}{y} = 4
    Then using a = 2, b = \dfrac{x}{y}, c = 4
    We can see that \dfrac{x}{y} = 2^4 = 16
    Thanks! It was a silly question as I realised as soon as I posted this! Thanks anyway
 
 
 
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