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    Draw the structure of the major organic product formed when an excess of R is reacted with bromomethane.

    R = CH3-CH2-C(NH2)(COOH) - H
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    (Original post by Chemisathtics)
    Draw the structure of the major organic product formed when an excess of R is reacted with bromomethane.

    R = CH3-CH2-C(NH2)(COOH) - H

    Think about it.
    You've got an amine, and a haloalkane.

    Have you ever learnt the organic mechanism between an amine and a haloalkane?
    Does nucleophilic substitution ring a bell?

    Spoiler:
    Show
    If not, amines have a lone pair of electrons on the nitrogen atom and so they can act as nucleophiles.

    In bromomethane, the bromine atom is more electronegative than carbon so it will attract the electrons in the bond. This makes the carbon slightly positive and it will be open to attack (by a nucleophile).

    The incoming amine will react with the bromoethane which will remove the bromine atom.

    Now you have an amine in which the nitrogen atom is making five bonds. So a hydrogen atom is removed (by another amine). The resulting product is your major organic product.
    Spoiler:
    Show
    The reason why is says major is because what you have made (hopefully) is a secondary amine. There are still a lone pair of electrons that will further attack the bromomethane but we can reduce subsequent reactions by having excess amine.
    http://www.chemguide.co.uk/mechanism...monia.html#top
 
 
 
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