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# Quick Question watch

1. How would you guys go about doing this question?

My initial thoughts are: The bottom right corner, BCD would make 180 - 50 = 130 degrees. However, from there I don't know where to go as it's two individual triangles and the information given in both triangles is insufficient in helping us to find out anything else about the triangles.
https://gyazo.com/28c672cc447b8d2be9aa53a56ae944f0
2. bump
3. bump
4. (Original post by Naruke)
How would you guys go about doing this question?

My initial thoughts are: The bottom right corner, BCD would make 180 - 50 = 130 degrees. However, from there I don't know where to go as it's two individual triangles and the information given in both triangles is insufficient in helping us to find out anything else about the triangles.
https://gyazo.com/28c672cc447b8d2be9aa53a56ae944f0
Start by looking at the big triangle ABC and find angle ABC using the sine rule.

Try this and then try to continue. Post all your working if you get stuck.
5. (Original post by Naruke)
bump
Be patient Your thread was at the top of the forum so it's not like people won't see it.

You posting will make people think your thread has an answer - threads with no replies are the ones that people will look at most. Also, labeling the thread as 'postgraduate' doesn't help.
6. (Original post by notnek)
Be patient Your thread was at the top of the forum so it's not like people won't see it.

You posting will make people think your thread has an answer - threads with no replies are the ones that people will look at most. Also, labeling the thread as 'postgraduate' doesn't help.

This is postgraduate
7. (Original post by notnek)
Start by looking at the big triangle ABC and find angle ABC using the sine rule.

Try this and then try to continue. Post all your working if you get stuck.
& What do you mean the big triangle? Don't you mean BCD?
8. (Original post by Naruke)
& What do you mean the big triangle? Don't you mean BCD?
No I mean the even bigger triangle ABC.
9. (Original post by notnek)
No I mean the even bigger triangle ABC.
How can that be considered a triangle o.0
10. (Original post by Naruke)
How can that be considered a triangle o.0
It has 3 sides : AB, BC and AC.
11. (Original post by Naruke)
This is postgraduate
You may be postgraduate but this is GCSE level maths and should be marked as that.
12. (Original post by notnek)
It has 3 sides : AB, BC and AC.
I didn't think triangles could be looked at like that, as it was joined to another smaller triangle. Well, thanks I'll make sure to remember this.

One more question plz:

https://gyazo.com/91fb197b8f3bf96c80f1f2885315a71f

part a) is the problem
13. (Original post by notnek)
You may be postgraduate but this is GCSE level maths and should be marked as that.
Nope, this is postgraduate maths
14. (Original post by notnek)
You may be postgraduate but this is GCSE level maths and should be marked as that.
But surely if you use the sine rule you need either two angles and one side or two sides and one angle?

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15. (Original post by Jeena_hunt5476)
But surely if you use the sine rule you need either two angles and one side or two sides and one angle?

Posted from TSR Mobile
Ignore what i said. I figured it out and yes ur right lol I learnt this last month while revising for my GCSE maths mock

Posted from TSR Mobile
16. (Original post by Jeena_hunt5476)
But surely if you use the sine rule you need either two angles and one side or two sides and one angle?

Posted from TSR Mobile
Correct.

But we do have enough : we have AB, AC and angle ACB which is 180 - 50 = 130.
17. (Original post by notnek)
Correct.

But we do have enough : we have AB, AC and angle ACB which is 180 - 50 = 130.
Haha yh I figured that out after lol!

Posted from TSR Mobile
18. (Original post by notnek)
Correct.

But we do have enough : we have AB, AC and angle ACB which is 180 - 50 = 130.
One more question plz:

https://gyazo.com/91fb197b8f3bf96c80f1f2885315a71f

part a) is the problem
19. (Original post by Naruke)
One more question plz:

https://gyazo.com/91fb197b8f3bf96c80f1f2885315a71f

part a) is the problem
I'm traveling now so won't be able to help for a few hours.

You could try posting a new thread with this question and don't reply to it. That will encourage people to reply to an unanswered thread.

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