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    Question is solve sin(6x)-cos(3x)=0 from x=0 to 2pi.

    Using double angle formula I simplified to 2sin(3x)cos(3x)-cos(3x)=0. I then took out a factor of cos(3x) and got left with cos(3x)=0 or 2sin(3x)-1=0. I solved both of them and overall got a massive 12 solutions which makes me think I've gone wrong somewhere? Like every other question I've ever done has an absolute max of 6. Is this just weird or have I gone wrong?

    The method is correct. WolframAlpha gives 12 solutions.
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Updated: February 16, 2016
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