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HARD physics problem Watch

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    There is a very tricky physics question which I couldn't do.

    If you can work out the answer then can you please tell me it and also I wouldn't mind showing me your working so I can understand how to do it

    Much appreciated:

    Q: Two 8 ohm resistors and a battery of emf 12.0V and internal resistance 8 ohm are connected in series with each other. Calculate i) the power delivered to each external resistor, ii) the power wasted due to internal resistance.
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    (Original post by STRANGER2)
    There is a very tricky physics question which I couldn't do.

    If you can work out the answer then can you please tell me it and also I wouldn't mind showing me your working so I can understand how to do it

    Much appreciated:

    Q: Two 8 ohm resistors and a battery of emf 12.0V and internal resistance 8 ohm are connected in series with each other. Calculate i) the power delivered to each external resistor, ii) the power wasted due to internal resistance.
    total resistance in the circuit = 8+8+8 ohms

    calculate current flowing using
    I=V/R

    using the calculated current you can get power in each resistor with
    P=I2R
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    P=V^2/R
    • Thread Starter
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    Thanks a lot!

    But how would I work out power wasted?
 
 
 
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