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#1
3Sin²x=sinxcosx

Find x where 0°≤x≤360°
0
4 years ago
#2
Bring the sinxcosx to LHS of equation. Factorise, consider when one of the 2 factors is 0, solve for x.
0
4 years ago
#3
(Original post by thefatone)
3Sin²x=sinxcosx

Find x where 0°≤x≤360°
you should use this site http://www.examsolutions.net/maths-r.../C3/module.php covers the spec very well. It's edexcel but hes got other spec too
0
#4
(Original post by Ano123)
Bring the sinxcosx to LHS of equation. Factorise, consider when one of the 2 factors is 0, solve for x.
i get sinx(3sinx-cosx)=0
what do i do with (3sinx-cosx)
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#5
(Original post by Shiv is Light)
you should use this site http://www.examsolutions.net/maths-r.../C3/module.php covers the spec very well. It's edexcel but hes got other spec too
This is C2
0
4 years ago
#6
(Original post by thefatone)
i get sinx(3sinx-cosx)=0
what do i do with (3sinx-cosx)
For the LHS to be 0, either sinx=0 or 3sinx=cosx.
0
4 years ago
#7
(Original post by thefatone)
This is C2
c3 for edexcel m8
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#8
(Original post by Shiv is Light)
c3 for edexcel m8
is it? i know you learn loads of trig identities in c3 but i do learn 2 identities in c2
and they are sinx/cosx=tanx and sin²x+cos²x=1
0
#9
(Original post by Ano123)
For the LHS to be 0, either sinx=0 or 3sinx=cosx.
thanks so much, that's where i went wrong
0
4 years ago
#10
(Original post by thefatone)
is it? i know you learn loads of trig identities in c3 but i do learn 2 identities in c2
and they are sinx/cosx=tanx and sin²x+cos²x=1
oh right, the question you posted doesn't use the trig identity you use in c3, my bad. You can still use exam solutions for c2. I got a B last year using exam solutions. Good luck m8!
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