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C2 Integration question watch

1. A question from Revision exercise 3, question 30.

First the area of the rectangle: a(1) = a
The area for A = rectangle - a
area of rectangle is bounded by y=1 and y=(x-a)^2
but the result doesn't seem to be correct.
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2. (Original post by bazlawth)
A question from Revision exercise 3, question 30.

First the area of the rectangle: a(1) = a
The area for A = rectangle - a
area of rectangle is bounded by y=1 and y=(x-a)^2
but the result doesn't seem to be correct.
It looks like you've made a rectangle which sometimes works but then you don't really have a way of finding A or the other part of your rectangle.

I think they want you to use another method (integration)
3. (Original post by bazlawth)
A question from Revision exercise 3, question 30.

First the area of the rectangle: a(1) = a
The area for A = rectangle - a
area of rectangle is bounded by y=1 and y=(x-a)^2
but the result doesn't seem to be correct.
As per Sean - in this case you want to find such that
4. (Original post by SeanFM)
It looks like you've made a rectangle which sometimes works but then you don't really have a way of finding A or the other part of your rectangle.

I think they want you to use another method (integration)
Mixed up sth, now I got the answer. Thanks!
5. nice question

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