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    Find the centre and radius of circle with equation x2 + y2 - 6x - 2y - 6 = 0
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    (Original post by AlphaArgonian)
    Find the centre and radius of circle with equation x2 + y2 - 6x - 2y - 6 = 0
    What have you tried?
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    (Original post by AlphaArgonian)
    Find the centre and radius of circle with equation x2 + y2 - 6x - 2y - 6 = 0
    Do you know the general method of completing the square with x and y?
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    Radius √6 centre (6,-2) i think
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    complete the square with the x and y terms respectively, and move all non-variables to the RHS.

    the square root of the RHS will be the radius, and the centre of the circle will be (-a, -b) where it is in the form (x + a)^2 + (y + b)^2 = r^2
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    (Original post by zetamcfc)
    What have you tried?
    Well I thought r would be root 6 but apparently that's wrong
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    1 simple question and 4 helpers !!
    (am I too late?)
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    (Original post by 13 1 20 8 42)
    Do you know the general method of completing the square with x and y?
    Ahhh that makes sense, I should've picked up on that
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    (Original post by TeeEm)
    1 simple question and 4 helpers !!
    (am I too late?)
    Yup, but still much appreciated that you offered aid
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    (Original post by AlphaArgonian)
    Yup, but still much appreciated that you offered aid
    more than enough here ...
    besides I just got up and it will take me at least 1 hour to start functioning ...
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    (Original post by TeeEm)
    more than enough here ...
    besides I just got up and it will take me at least 1 hour to start functioning ...
    Lol it takes me 2-3 hours to properly wake up
 
 
 
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