Anyone able to help me with this parametric equation?
d^2y/dx^2 = t^2 +1
dy/dx = t^3 + 2t
Find x(t) given that x(1) = 4
I've started off by doing the simple dy/dx = (dy/dt) / (dt/dx) and d^2y/dx^2 = d/dt(dy/dx) x dt(dx), I just don't have a clue what to do after it. Thanks in advance.
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- Thread Starter
- 19-02-2016 17:31
- 22-02-2016 10:16
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- 22-02-2016 19:26
d^2y/dx^2 = d/dx(dy/dx)/(dx/dt)
Differentiate dy/dx and substitute the values for d^2y/dx^2 and d/dx(dy/dx).
rearrange for dx/dt.
Integrate dx/dt to find x(t). Use x(1) = 4 to find the constant from integration.
- 30-03-2016 00:09
I need help too...
What is A10 even asking? It looks like a sequence question to me? Why is Sn(1) not 1+2+3+...+n(1)^(n-1)?