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    Anyone able to help me with this parametric equation?

    d^2y/dx^2 = t^2 +1

    dy/dx = t^3 + 2t

    Find x(t) given that x(1) = 4





    I've started off by doing the simple dy/dx = (dy/dt) / (dt/dx) and d^2y/dx^2 = d/dt(dy/dx) x dt(dx), I just don't have a clue what to do after it. Thanks in advance.
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    Got strong views on Maths? @MathsScot wants to hear them - fill in the survey and help shape the future of maths in Scotland. bit.ly/mmcount
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    d^2y/dx^2 = d/dx(dy/dx)/(dx/dt)
    Differentiate dy/dx and substitute the values for d^2y/dx^2 and d/dx(dy/dx).
    rearrange for dx/dt.
    Integrate dx/dt to find x(t). Use x(1) = 4 to find the constant from integration.
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    I need help too...
    http://www.millburnacademy.co.uk/wp-...06/AH-2002.pdf
    What is A10 even asking? It looks like a sequence question to me? Why is Sn(1) not 1+2+3+...+n(1)^(n-1)?

    Thanks
 
 
 
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