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    Hey, how can you tell which way around the conjugate base pair is in an equation?
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    (Original post by Hardy jacks)
    Hey, how can you tell which way around the conjugate base pair is in an equation?
    A conjugate acid -base pair differ in structure by ONLY ONE HYDROGEN ION.

    The Bronsted Lowry acid donates a proton on its side of the reaction and its conjugate base accepts a proton on the other side of the reaction.
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    (Original post by charco)
    A conjugate acid -base pair differ in structure by ONLY ONE HYDROGEN ION.

    The Bronsted Lowry acid donates a proton on its side of the reaction and its conjugate base accepts a proton on the other side of the reaction.
    Ahh I see thank you and from that it's possible to work out the conjugate acid and bronsted Lowry base and conjugate acid?
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    (Original post by charco)
    A conjugate acid -base pair differ in structure by ONLY ONE HYDROGEN ION.

    The Bronsted Lowry acid donates a proton on its side of the reaction and its conjugate base accepts a proton on the other side of the reaction.
    Is this the correct labels for this equation?
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    (Original post by Hardy jacks)
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    Is this the correct labels for this equation?
    Both pairs of acid-base are conjugate acid bases here. The usual way to label is 'acid 1 - base 1' and 'acid 2 - base 2'
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    (Original post by Serine Soul)
    Both pairs of acid-base are conjugate acid bases here. The usual way to label is 'acid 1 - base 1' and 'acid 2 - base 2'
    So how would you label this equation in terms of conjugate base pairs?...Name:  image.jpg
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    (Original post by Hardy jacks)
    So how would you label this equation in terms of conjugate base pairs?...Name:  image.jpg
Views: 128
Size:  503.4 KB(ignore the text)
    As charco said, in conjugate acid base pairs, the acid and base differ by one hydrogen ion.

    In this equation, we can see that HNO3 and NO3- differ from each other by a hydrogen ion (let that be acid-base pair 1) as do HCOOH and HCOOH2+ (let that be acid base pair 2)

    An acid donates a H+, and its conjugate base accepts a H+, using that, you can work out what the acid is and what the base is in each pair
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    (Original post by Serine Soul)
    As charco said, in conjugate acid base pairs, the acid and base differ by one hydrogen ion.

    In this equation, we can see that HNO3 and NO3- differ from each other by a hydrogen ion (let that be acid-base pair 1) as do HCOOH and HCOOH2+ (let that be acid base pair 2)

    An acid donates a H+, and its conjugate base accepts a H+, using that, you can work out what the acid is and what the base is in each pair
    Thanks for your help I get it now
 
 
 
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