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# Maths question watch

1. I got 4sin(x+48.59) for part 11a but have no clue how to do 11b) could someone please help
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2. (Original post by Jism1495)
I got 4sin(x+48.59) for part 11a but have no clue how to do 11b) could someone please help
Use the fact that since you know that oscillates between and . The minimum value of will be when the denominator is the largest. And you know what the largest the denominator can get... look at my inequality.
3. (Original post by Jism1495)
I got 4sin(x+48.59) for part 11a but have no clue how to do 11b) could someone please help
I've posted a detailed explanation of what's going on (for a different question but same thing really) here. It might be beneficial for you to have a read over it, just in case.
4. (Original post by Zacken)
I've posted a detailed explanation of what's going on (for a different question but same thing really) here. It might be beneficial for you to have a read over it, just in case.
Thank you, do you have a link to it?
5. (Original post by Jism1495)
Thank you, do you have a link to it?
****, I'm dumb - http://www.thestudentroom.co.uk/show...postcount=2361 here you go.

Basically, explot the fact that is boundede between and .
6. (Original post by Zacken)
****, I'm dumb - http://www.thestudentroom.co.uk/show...postcount=2361 here you go.

Basically, explot the fact that is boundede between and .
I'm still confused, could you tell me the answer you got and I shall try to work towards it, thank yiu
7. (Original post by Jism1495)
I'm still confused, could you tell me the answer you got and I shall try to work towards it, thank yiu
The denominator is maximum with a max value of 4. Max (f) = 20/4.
8. (Original post by Zacken)
The denominator is maximum with a max value of 4. Max (f) = 20/4.
Thanks, I knew it wouldn't be that hard it's just too late at night nothing's making sense and it's so frustrating
9. (Original post by Jism1495)
Thanks, I knew it wouldn't be that hard it's just too late at night nothing's making sense and it's so frustrating
Do you happen to know how to do this question? It's the last one I have to do and it looks nothing like trig equations I've done before where I can substitute something in
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10. (Original post by Jism1495)
Do you happen to know how to do this question? It's the last one I have to do and it looks nothing like trig equations I've done before where I can substitute something in
Do the Rsin (x+ alpha) thing on the two trig terms and then solve it = -3.
11. (Original post by Zacken)
Do the Rsin (x+ alpha) thing on the two trig terms and then solve it = -3.
Okay thanks, for future questions how would I know whether to use rcos or rsin?
12. You can use either. The value of alpha will just be different in each case.

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