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OCR A2 CHEMISTRY F324 and F325- 14th and 22nd June 2016- OFFICIAL THREAD

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Original post by TSR121
Guys for the ketone on the last question was it 5 carbons in a row then the c=o on the middle carbon ?


I put it in the middle one too! i wasn't sure whether it was specific to anywhere in the middle :s-smilie:
image.jpeg I got this for F
Original post by RealistZ
It's propanoic acid CH3CH2COOH Mr=74


The second product of the ethanoic anhydride reaction was ethanoic acid
image.jpeg I got this for G
Original post by WhatALad
They did 3/94=0.032
0.032/0.61=0.0528
0.0528*135=7.1


It's 0.032* 0.61
Original post by ali_t9001
The second product of the ethanoic anhydride reaction was ethanoic acid


You are thinking of a different question.
image.jpeg I got this for H (m/r of 74. Propanoic acid)
Guys how's 2.66 the correct answer? I got that first but then when I did the inverse is didn't give me 61% so I wasn't sure whether that was correct.. I changed my answer to 7.14 cause then I ended up getting a 61% yield but hey if 2.66 is correct then ;(
People have got to remember highest ever boundary was 51/60, paper was average in hardness so A boundary probably around 48/60.
Anyone got 2.86g for the mass of compound A?
image.jpeg I got this for the ester I
Original post by student.1997
Was compound J (CH3)3C=oCH3


no, (CH3)3CH2OH i believe
image.jpeg I got this for J
What was the proton NMR splitting pattern? :s-smilie: I think I got doublet multiplet and triplet?
Will you get ecf of you got f wrong?
Reply 1895
Can someone do a proper unofficial mark scheme please
Original post by KB_97
image.jpeg I got this for F


Is displayed formula okay?
Original post by Yhuikopn
Will you get ecf of you got f wrong?


Yeah I think you would :smile:
For the PLA question on chiral synthesis and using fermentation of sugars, I spoke about producing more than one optical isomer when using chiral synthesis. Is this right? Or is it to do with one being natural and the other isn't?
Original post by KB_97
image.jpeg I got this for J


Yep, I got this too.

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