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    Name:  image.jpg
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Size:  365.8 KBHow do u do the integration question
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    I think you should get a better picture coz it like half cut off
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    Assuming you mean the top one with sine squared in it - use a double angle identity.
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    use cos2A = cos^2(A)-sin^2(A)

    but let A = 3x
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     \displaystyle \sin^2x \equiv \frac{1}{2} (1-\cos{2x})
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    If you find it hard to remember the formula of cos2a=... in all its different forms i find it useful to use that cos2a=cos^2(x)-sin^2(x) and work from there as needed
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    If the integral of a term isn't known, use an identity that you know to write it differently into something you do know how to integrate.

    Such as quoted:

    (Original post by B_9710)
     \displaystyle \sin^2x \equiv \frac{1}{2} (1-\cos{2x})
    (Separate each term after this and integrate as you know how to).
 
 
 
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