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# GCSE Chemistry: Quantitive chemistry question watch

1. If anyone could help me with this question it would be much appreciated
NaOH + HCl -> NaCl + H2O
A 25cm3 sample of NaOH (0.125mol/dm3) required 21.6cm3 of HCl for complete neutralisation
A) calculate the number of moles of NaOH neutralised by the hydrochloric acid
I got 2.7 moles
B) use the balanced equation to deduce the number of moles of hydrochloric acid in 21.6cm3
Is part b even in english
2. (Original post by Jamiemcq)
If anyone could help me with this question it would be much appreciated
NaOH + HCl -> NaCl + H2O
A 25cm3 sample of NaOH (0.125mol/dm3) required 21.6cm3 of HCl for complete neutralisation
A) calculate the number of moles of NaOH neutralised by the hydrochloric acid
I got 2.7 moles
incorrect

Moles = molarity x volume(in litres)
3. (Original post by charco)
incorrect

Moles = molarity x volume(in litres)
Molarity?
Ive learnt it as
No. Of moles = concentration × volume
4. (Original post by Jamiemcq)
Molarity?
Ive learnt it as
No. Of moles = concentration × volume
molarity = concentration in moles per litre

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