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# Help with this log graph problem watch

1. Clearly the acceleration due to gravity that we need to find here is 9.8 but i guess we have to show that graphically? How do i do that? Do i convert the graph into a linear graph first by taking the log of both sides?
2. T=2pisqrt(L/g) -> sqrt(L/g)=T/2pi -> L/g = T^2/(4pi^2) -> L/T^2 = g/(4pi^2) -> L = g/(4pi^2) * T^2, so plot L against T^2. The gradient of the line of best fit should be g/(4pi^2).
3. (Original post by constellarknight)
T=2pisqrt(L/g) -> sqrt(L/g)=T/2pi -> L/g = T^2/(4pi^2) -> L/T^2 = g/(4pi^2) -> L = g/(4pi^2) * T^2, so plot L against T^2. The gradient of the line of best fit should be g/(4pi^2).
I did do that to get 9.7 but i want to know why i graphed L against T^2 and not just T?
4. g/4pi^2 = 0.245 -> g = 0.245 * 4pi^2 = 9.672..., which is a reasonable approximation.

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