18000 (0.85)^n^-^1 < 5000
(0.85)^n^-^1 < \frac {5}{18}
log (0.85)^n^-^1 < log \frac {5}{18}
n-1 < \frac {log \{5}{18}}{log 0.85)
18000 (0.85)^n^-^1 < 5000
(0.85)^n^-^1 < \frac {5}{18}
log (0.85)^n^-^1 < log \frac {5}{18}
n-1 < \frac {log \{5}{18}}{log 0.85)
(0.85)^n^-^1 < \frac {5}{18}
log (0.85)^n^-^1 < log \frac {5}{18}
(0.85)^n^-^1 < \frac {5}{18}
log (0.85)^n^-^1 < log \frac {5}{18}
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