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# Integration - hyperbolic functions watch

1. If

Why doesn't ?
2. Anyone?????????
3. (Original post by Ano123)
Anyone?????????
how do you know that it is wrong ?

4. Cuz you can't distribute negative like that (3rd step)
5. (Original post by GUMI)
Cuz you can't distribute negative like that (3rd step)
Why not?
6. (Original post by the bear)
how do you know that it is wrong ?

It doesn't give the same result if you do it by partial fractions (it does work without the negative - it works fine for both methods)
7. (Original post by Ano123)
If

Why doesn't ?
I think maybe because (giving you what is in the formula booklet) so:

So they both work (I think).
8. (Original post by Ano123)
Anyone?????????
Who say's it's incorrect? That's perfectly fine. Just remember your modulus signs.
9. (Original post by Zacken)
Who say's it's incorrect? That's perfectly fine. Just remember your modulus signs.
Yeah I figured that it had to be correct haha.
10. It definitely works. You can simply factor out -1.
11. When I do using hyperbolics i get
When I do it by partial fractions I get
12. Is .
Is there an absolute inside the log?
13. (Original post by Ano123)
When I do using hyperbolics i get
When I do it by partial fractions I get
You don't get either of those, slap on those modulus signs!
14. (Original post by Ano123)
Is .
Is there an absolute inside the log?
Yes, you can't have the logarithm of a negative number in the real plane.
15. (Original post by Ano123)
When I do using hyperbolics i get
When I do it by partial fractions I get
you need mods
16. Damn. Makes sense now.
I always used to put the mod signs but for some reason I started thinking that it wasn't right like that.
17. (Original post by TeeEm)
you need mods
How you doing sir
18. (Original post by It'sDuckFam)
How you doing sir
very good ..
I am teaching now
19. Is this further maths
20. (Original post by under8ed)
Is this further maths
Yes.
Well, hyperbolic functions only appear at further, partial fractions is core 4

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