Can anyone help with these questions? Thanks!
Multiple choice Q11 and Q14 from the specimen paper:
I keep getting D for Q14 but apparently the answer is B :/
Multiple choice Q8 from exemplar paper:
I have no idea what the question is even asking!
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Last edited by mariabrightside; 23-02-2016 at 19:27.
- 23-02-2016 17:34
- 23-02-2016 22:21
Q14:Spoiler:Q8:ShowAssuming you got the following balanced equation:
2IO3 + 12H+-> I2 + 6H2O
You'll notice that this equation produces I2. This is 2 moles of Iodine, as in it's natural state Iodine is two molecules bound together.
To get I- on it's own (1 mole) you'd divide the whole equation by two. This would give you:
IO3 + 6H+-> I-+ 3H2O
Which satisfies B.Spoiler:I hope this helped slightly!ShowThis question is a bit misleading in my opinion - as the base structure is the same, the only bits that really matter are:
The question tells you that the oxygen is labelled as 1 and going anticlockwise this number increases so the carbon next to it is labelled 2, the one after 3 and so on up to 6.
Using the simple nomenclature rules we know that the 4-hydroxy means there needs to be an OH group attached to the fourth carbon, and the 6-methyl means there needs to be a CH3 group attached to the 6th carbon. The only compound which satisfies both of these requirements is B.