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    Can anyone help with these questions? Thanks!

    Multiple choice Q11 and Q14 from the specimen paper:
    http://www.sqa.org.uk/files_ccc/ChemistrySQPH.pdf
    I keep getting D for Q14 but apparently the answer is B :/

    Multiple choice Q8 from exemplar paper:
    http://www.sqa.org.uk/files_ccc/ChemistryEQPH.pdf
    I have no idea what the question is even asking!
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    Q14:
    Spoiler:
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    Assuming you got the following balanced equation:
    2IO3 + 12H+-> I2 + 6H2O

    You'll notice that this equation produces I2. This is 2 moles of Iodine, as in it's natural state Iodine is two molecules bound together.
    To get I- on it's own (1 mole) you'd divide the whole equation by two. This would give you:
    IO3 + 6H+-> I-+ 3H2O
    Which satisfies B.
    Q8:
    Spoiler:
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    This question is a bit misleading in my opinion - as the base structure is the same, the only bits that really matter are:

    4-hydroxy
    6-methyl

    The question tells you that the oxygen is labelled as 1 and going anticlockwise this number increases so the carbon next to it is labelled 2, the one after 3 and so on up to 6.

    Using the simple nomenclature rules we know that the 4-hydroxy means there needs to be an OH group attached to the fourth carbon, and the 6-methyl means there needs to be a CH3 group attached to the 6th carbon. The only compound which satisfies both of these requirements is B.
    I hope this helped slightly!
 
 
 
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