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    Hello guys, I really dont have time to read all those pages lol. If someone could tell me what important stuff has been said about the exam e.g. Predictions etc. that would be greatly appreciated
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    Ok thanks, but if travelling up the plane, the component of weight will be down and if travelling down the plane in the opposite direction?
    (Original post by ryandaniels2015)
    Ok thanks, but if travelling up the plane, the component of weight will be down?
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    (Original post by ryandaniels2015)
    Ok thanks, but if travelling up the plane, the component of weight will be down and if travelling down the plane in the opposite direction?
    the component of weight is always down. may be positive or negative force in f=ma depending on direction of movement
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    So as follows....
    (Original post by candol)
    the component of weight is always down. may be positive or negative force in f=ma depending on direction of movement
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    (Original post by ryandaniels2015)
    So as follows....
    Sorry oops i meant the 3g sin theta in the opposite direction
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    Guys for this question, why are -2U and -6MU not allowed for the speed and the impulse?

    For part a I done:
    (2m)(u)+(3m)(-4u)=(5m)v
    I then solved for v to give me -2u but in the mark scheme it says -2u is A0 and only 2u is allowed?

    For impulse I then done (for truck P):
    (-2u)(2m)-(2m)(2u) to give me -6mu, but the answer is 6mu..
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    (Original post by particlestudent)
    Guys for this question, why are -2U and -6MU not allowed for the speed and the impulse?

    For part a I done:
    (2m)(u)+(3m)(-4u)=(5m)v
    I then solved for v to give me -2u but in the mark scheme it says -2u is A0 and only 2u is allowed?

    For impulse I then done (for truck P):
    (-2u)(2m)-(2m)(2u) to give me -6mu, but the answer is 6mu..
    You got it right. You just have to write down "therefore Impulse=6mu Ns". This is what our teacher said.

    I'm not quite sure about part a
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    (Original post by ryandaniels2015)
    Sorry oops i meant the 3g sin theta in the opposite direction
    its always down the slope
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    (Original post by candol)
    its always down the slope
    Ok Thanks
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    (Original post by particlestudent)
    Guys for this question, why are -2U and -6MU not allowed for the speed and the impulse?

    For part a I done:
    (2m)(u)+(3m)(-4u)=(5m)v
    I then solved for v to give me -2u but in the mark scheme it says -2u is A0 and only 2u is allowed?

    For impulse I then done (for truck P):
    (-2u)(2m)-(2m)(2u) to give me -6mu, but the answer is 6mu..

    also speed isn't a vector quantity, so it cant have direction

    "magnitude"
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    (Original post by boredom07)
    You got it right. You just have to write down "therefore Impulse=6mu Ns". This is what our teacher said.

    I'm not quite sure about part a
    I'm not sure why it says -2u is A0 then. Maybe because it wanted speed, the negative sign was not necessary?
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    (Original post by KloppOClock)
    also speed isn't a vector quantity, so it cant have direction

    "magnitude"
    Oh thanks, I didn't read think of that
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    anyone got any general last minute tips for the M1 exam?

    mine would be to check if the question is asking for acceleration/decelleration or speed/velocity as ive lost a few marks from giving the wrong answer.
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    https://3b0a7b1bc87f5381e60f8f717510...%20Edexcel.pdf

    Can someone help with question 7) (C) Thanks much appreciated!
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    (Original post by particlestudent)
    I'm not sure why it says -2u is A0 then. Maybe because it wanted speed, the negative sign was not necessary?
    Yeah, what you said is right. Speed can never be negative so you'll need to take away the negative sign.
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    Have some hard questions, would appreciate some help. Dont know how to do question C on here.
    http://postimg.org/image/v6x6v9hcb

    I also dont understand what the forces on each of the blocks on here are:
    http://postimg.org/image/z0nxjphjf
    The book isnt very clear on that.

    Also how do you work out part c on here:
    http://postimg.org/image/vjsrjckjv
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    (Original post by fpmaniac)
    Have some hard questions, would appreciate some help. Dont know how to do question C on here.
    http://postimg.org/image/v6x6v9hcb

    I also dont understand what the forces on each of the blocks on here are:
    http://postimg.org/image/z0nxjphjf
    The book isnt very clear on that.

    Also how do you work out part c on here:
    http://postimg.org/image/vjsrjckjv
    you might want to check your images out
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    (Original post by fpmaniac)
    Have some hard questions, would appreciate some help. Dont know how to do question C on here.
    http://postimg.org/image/v6x6v9hcb

    I also dont understand what the forces on each of the blocks on here are:
    http://postimg.org/image/z0nxjphjf
    The book isnt very clear on that.

    Also how do you work out part c on here:
    http://postimg.org/image/vjsrjckjv
    Question Three:
    Spoiler:
    Show

    Apply F=MA to both objects, solve simultaneously to eliminate T and find A.

    Use suvat to find final velocity of B as it hits the ground.

    Use F=MA on A after B has landed where friction is the only force to find new acceleration.

    Apply SUVAT to A using U as your old final velocity, V as 0, A as your new velocity, and S as the unknown.



    Question Two:
    Spoiler:
    Show

    Forces acting on A?

    R (/\) R>0.4g

    Apply F=MA

    R-0.4g = 0.4 x 0.5


    Question One:
    Spoiler:
    Show
    V^2=U^2 + 2as
    V^2 =2(2g/5)0.25

    Sub V, M and U into I=M(V-U)
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    (Original post by candol)
    you might want to check your images out
    the link seems to work for me doesnt it work for you

    (Original post by KloppOClock)
    can i have the answer to part a
    Answer to part a) is 18N
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    (Original post by fpmaniac)
    the link seems to work for me doesnt it work for you



    Answer to part a) is 18N
    yh turns out you didnt need it, check my last post as i edit it
 
 
 
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