Turn on thread page Beta
    Offline

    10
    ReputationRep:
    How is it that I've done all the past year papers but I still feel ill prepared I'm still making careless mistakes and such, it's frustrating.
    Offline

    11
    ReputationRep:
    I've done no revision at all yet lol , gonna do a few hours of revision and past papers now
    aiming for 100 UMS but ill end up with like 95 due to stupid mistakes as usual
    Offline

    12
    ReputationRep:
    Can someone explain Q7 to me, please?

    https://drive.google.com/file/d/0B1Z...M2V1FZTnM/view
    Offline

    10
    ReputationRep:
    Name:  3851e6e6c2ccdbb02b472a5430ede9c5.png
Views: 130
Size:  87.1 KBdidnt get chance before so thanks Zacken for helping me last time . anyways for this question (June 2014 R) for part b) i got that s = 0.3m but the mark scheme says you need to do 0.3 x 2 to get the answer and i don't understand why?
    Offline

    2
    ReputationRep:
    (Original post by KloppOClock)
    Thrust is opposite to tension.

    Tension:

    O---->-------<-----O

    Thrust:

    O<---->O
    (Original post by wenogk)
    Thank you!


    This question uses "thrust" check out examsolutions video for that question(Q6)
    http://www.examsolutions.net/a-level...e/paper.php#Q6
    Ahh right thanks :yy:

    Posted from TSR Mobile
    Offline

    18
    ReputationRep:
    Just did the specimen paper, what are the boundaries?
    Offline

    17
    ReputationRep:
    (Original post by Thomith)
    Name:  3851e6e6c2ccdbb02b472a5430ede9c5.png
Views: 130
Size:  87.1 KBdidnt get chance before so thanks Zacken for helping me last time . anyways for this question (June 2014 R) for part b) i got that s = 0.3m but the mark scheme says you need to do 0.3 x 2 to get the answer and i don't understand why?
    The particle returns to the point where the tension is lost. So it will travel back the same distance hence x 2.
    Offline

    10
    ReputationRep:
    (Original post by AlphaArgonian)
    Can someone explain Q7 to me, please?

    https://drive.google.com/file/d/0B1Z...M2V1FZTnM/view
    Arsey's way is superior imo, but hope this helps. Name:  For some guy.jpeg
Views: 123
Size:  232.5 KB
    Offline

    17
    ReputationRep:
    (Original post by AlphaArgonian)
    Can someone explain Q7 to me, please?

    https://drive.google.com/file/d/0B1Z...M2V1FZTnM/view
    I used (v-u)/t = acceleration
    So : 2i+9j – (-3i-3j) divided by t
    = (5i + 12j)/t

    Gives us the magnitude therefore:
    (5/t)^2 + (12/t)^2 = 2.6^2
    = 25/(t^2) + 144/(t^2) = 6.76

    Multiply all my t^2 to get 169=6.76t^2
    SoT= 5

    Sub this into the first part (5i +12j)/5 = 1 and 2.4 
    Offline

    17
    ReputationRep:
    (Original post by Marxist)
    Arsey's way is superior imo, but hope this helps. Name:  For some guy.jpeg
Views: 123
Size:  232.5 KB
    Got there before me

    My method is a tad different tho, shocked I got it right tbh haha.
    Offline

    17
    ReputationRep:
    (Original post by Louiseelg0rt)
    When a vector is A relative to B, is that the same as the vector BA? or is it the vector AB?
    A relative to B is BA
    Offline

    4
    ReputationRep:
    Anyone found any *really* hard questions that come up?

    And I just can't get my head around "what does inextensible show/how have you used that in your calculation" kinda questions.
    Offline

    9
    ReputationRep:
    (Original post by thelegend99)
    Anyone found any *really* hard questions that come up?

    And I just can't get my head around "what does inextensible show/how have you used that in your calculation" kinda questions.
    inextinsible string means that acceleration of both particles attached will be the same
    Offline

    9
    ReputationRep:
    (Original post by thelegend99)
    Anyone found any *really* hard questions that come up?

    And I just can't get my head around "what does inextensible show/how have you used that in your calculation" kinda questions.
    This is because as soon as one particle moves, the other one moves with it since the string can't stretch!
    Offline

    1
    ReputationRep:
    For vectors, does it matter whether we write them in i + j form, or the other form with the brackets (forgot their name!)?
    Offline

    10
    ReputationRep:
    How do we use the information that the string is light?

    Also, for questions where the string breaks, that would mean that the tension in the string is now 0 and so we would have to find the new acceleration for the particle, right?
    Offline

    10
    ReputationRep:
    (Original post by thesuperdark)
    For vectors, does it matter whether we write them in i + j form, or the other form with the brackets (forgot their name!)?
    doesn't matter i think, but i usually leave them as i and j as the final answer
    Offline

    14
    ReputationRep:
    (Original post by amelienine)
    How do we use the information that the string is light?

    Also, for questions where the string breaks, that would mean that the tension in the string is now 0 and so we would have to find the new acceleration for the particle, right?
    i think that means the tension and acceleration are the same
    Offline

    3
    ReputationRep:
    (Original post by Don Pedro K.)
    This is because as soon as one particle moves, the other one moves with it since the string can't stretch!
    There u go its the ultimate HARD GOLD TIER M1 !
    I hope u like this for practice!
    Attached Images
  1. File Type: pdf 15 Gold 5 - M1 Edexcel.pdf (198.2 KB, 76 views)
    Offline

    9
    ReputationRep:
    (Original post by KloppOClock)
    i think that means the tension and acceleration are the same
    Pretty sure the fact that tension is the same is given by "string passes over a smooth pulley" from what I remember
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: October 25, 2016

2,785

students online now

800,000+

Exam discussions

Find your exam discussion here

Poll
Should universities take a stronger line on drugs?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.