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# Edexcel AS/A2 Mathematics M1 - 8th June 2016 - Official Thread watch

1. If you get the right answer with working that is different (but still valid) from the mark scheme do you get full credit mark wise?
2. (Original post by audreygal)
Hey guys, I was wondering if anyone had a link to the 2015 M1 paper?
Edexcel website?

http://qualifications.pearson.com/co...e_20150603.pdf
3. This thread is beginning to get repetitive!
4. Good luck everyone
5. (Original post by KloppOClock)
Good luck everyone
You too! I'm just going over vectors for 20 minutes on ExamSolutions then I'm sleeping. How many hours sleep are you going to give yourself?
6. (Original post by jtlmao)
Force on bottom block will be equal to the weight of the top block and bottom block combined
Which force? If you mean the reaction from the floor of the lift, they are only equal if there is no acceleration.
7. (Original post by KloppOClock)
Good luck everyone
Hey on that Mr. Barton thing you just linked, how come the weight of the lift is 600g + N when N is acting upwards?
8. (Original post by particlestudent)
You too! I'm just going over vectors for 20 minutes on ExamSolutions then I'm sleeping. How many hours sleep are you going to give yourself?
6 probably, gonna wake up early and do last minute panic revision
9. (Original post by HopelessMedic)
Could anyone explain what you do when one vector is, for example south west of another? I know its something to do with knowing they make an isosceles triangle but still a bit confused on the method. Thanks in advance
I believe what happens here is because south west is a direction which would have a bearing of 225, and tan 225=1, and tan^-1(i components/j components)=225, i components/j components = 1, so then you just make the components equal one another and solve for the unknown value (if that makes sense?)
10. (Original post by Don Pedro K.)
Hey on that Mr. Barton thing you just linked, how come the weight of the lift is 600g + N when N is acting upwards?
it literally says in the paragraph lol

"don’t forget Newton’s third law therewill be some ‘equal and opposite’ pairs of forces"

"If the normal reaction on the man is N newtons then this means that the liftfloor is pushing up on the man with a force of N newtons and therefore theman must be pushing down on the lift floor with an equal sized force of Nnewtons."
11. (Original post by Brackno)
I believe what happens here is because south west is a direction which would have a bearing of 225, and tan 225=1, and tan^-1(i components/j components)=225, i components/j components = 1, so then you just make the components equal one another and solve for the unknown value (if that makes sense?)
Actually j and i components the other way around sorry!
12. (Original post by KloppOClock)
it literally says in the paragraph lol

"don’t forget Newton’s third law therewill be some ‘equal and opposite’ pairs of forces"

"If the normal reaction on the man is N newtons then this means that the liftfloor is pushing up on the man with a force of N newtons and therefore theman must be pushing down on the lift floor with an equal sized force of Nnewtons."
ahhh yeah okay haha xD I've never seen anything like that before o.O Hoping lifts don't come up tbh haha
13. Would someone be able to teach me M1? Like I need to know the topics we will be asked about and how to answer the questions etc.
14. Good luck everyone. It will go well.
15. (Original post by rohanmcdermott)
Would someone be able to teach me M1? Like I need to know the topics we will be asked about and how to answer the questions etc.
when do you need to know it by?
16. What are the different assumptions you can make?
17. (Original post by KloppOClock)
when do you need to know it by?
9AM
18. (Original post by rohanmcdermott)
Would someone be able to teach me M1? Like I need to know the topics we will be asked about and how to answer the questions etc.
bit late
19. (Original post by rohanmcdermott)
9AM
just go to exam solutions
20. (Original post by rohanmcdermott)
9AM
http://www.examsolutions.net/maths-r.../M1/module.php

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