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Edexcel AS/A2 Mathematics M1 - 8th June 2016 - Official Thread watch

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    (Original post by audreygal)
    I found the model answers one, but would like to sit a lil mock for myself before I go to bed.
    http://qualifications.pearson.com/en...une-2015#step4
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    (Original post by KloppOClock)
    6 probably, gonna wake up early and do last minute panic revision
    6 should be okay

    I honestly don't think it'll go too bad, I just hope a question with two boxes on top of each other in a lift doesn't come up...
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    I feel so stupid! Thank you.
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    (Original post by rohanmcdermott;[url="tel:65545775")
    65545775[/url]]Would someone be able to teach me M1? Like I need to know the topics we will be asked about and how to answer the questions etc.
    This was literally me with stats last year, walked into my maths class the day before exams....teacher asks which bits need work...opens book at page 1.... Bloody stats
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    (Original post by particlestudent)
    6 should be okay

    I honestly don't think it'll go too bad, I just hope a question with two boxes on top of each other in a lift doesn't come up...
    is there a question similar , i can have a go at?
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    No friction if plane is smooth

    If string is light there is no weight

    If string is Inextensible the magnitude of acceleration is the same for both particles

    If the pulley is smooth the tension in string is same on both sides

    If particle moves freely under gravity then take the acceleration as 9.8 if going down

    If rod is uniform the weight acts at the midpoint.

    F = ma

    Friction = R X mu

    Distance = area

    Gradient = acceleration

    Momentum = mass X velocity

    Impulse = mv - mu

    Total momentum before impact = total momentum after impact

    If rod is about to tilt, the other supports force is equal to 0

    V = (r - r0) /t

    r = r0 + tv

    Velocity = (speed / magnitude of direction vector ) X direction vector

    Magnitude of a vector = square root (i^2 + j^2)

    V = u + at

    S = ut + 1/2 X a X t^2

    V^2 = u^2 + 2 X a X s

    S = 1/2(u + v)t

    S = vt - 1/2 x a X t ^2
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    (Original post by particlestudent)
    6 should be okay

    I honestly don't think it'll go too bad, I just hope a question with two boxes on top of each other in a lift doesn't come up...
    knowing our luck that will be the last question
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    Did anyone who has done the very last gold paper the ultimate one actually do well......I thought I knew m1 then that ruined me.....I'm just glad every single question won't be on that level....
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    (Original post by Exams987)
    is there a question similar , i can have a go at?
    I'm struggling to find one but I'm sure it's came up before. I might just ignore it though because the likelihood of it coming up seems small..
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    (Original post by philo-jitsu)
    Did anyone who has done the very last gold paper the ultimate one actually do well......I thought I knew m1 then that ruined me.....I'm just glad every single question won't be on that level....
    it has really low grade boundaries. however, dont just correct your mistakes, you need to understand why you were wrong and why whatever was right was right
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    (Original post by alluaugust;[url="tel:65546377")
    65546377[/url]]No friction if plane is smooth

    If string is light there is no weight

    If string is Inextensible the magnitude of acceleration is the same for both particles

    If the pulley is smooth the tension in string is same on both sides

    If particle moves freely under gravity then take the acceleration as 9.8 if going down

    If rod is uniform the weight acts at the midpoint.

    F = ma

    Friction = R X mu

    Distance = area

    Gradient = acceleration

    Momentum = mass X velocity

    Impulse = mv - mu

    Total momentum before impact = total momentum after impact

    If rod is about to tilt, the other supports force is equal to 0

    V = (r - r0) /t

    r = r0 + tv

    Velocity = (speed / magnitude of direction vector ) X direction vector

    Magnitude of a vector = square root (i^2 + j^2)

    V = u + at

    S = ut + 1/2 X a X t^2

    V^2 = u^2 + 2 X a X s

    S = 1/2(u + v)t

    S = vt - 1/2 x a X t ^2

    Awesome....was gonna look up the arsey revision thread but this has it all....thanks for this!
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    (Original post by Exams987)
    is there a question similar , i can have a go at?
    gold paper 5 if you havent done it
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    (Original post by rohanmcdermott)
    9AM
    sure lets do an all nighter
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    (Original post by KloppOClock;[url="tel:65546483")
    65546483[/url]]it has really low grade boundaries. however, dont just correct your mistakes, you need to understand why you were wrong and why whatever was right was right
    I agree....a mistake = a gap In knowledge....it was just so many gaps all at once lol....understand it now though
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    (Original post by philo-jitsu)
    I agree....a mistake = a gap In knowledge....it was just so many gaps all at once lol....understand it now though
    well you understand gold 5 then you're definitely ready for whatever comes up!
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    Guys just a last minute panic check; if moving parallel to i, the j component = 0 and vice versa right??

    And if north-west then??
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    If you get the right answer with working that is different (but still valid) from the mark scheme do you get full credit mark wise?
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    is there an error carried forward in M1?

    like i do sooo many silly mistakes because of the hurry, such as signs mistakes.
    especially for the questions that you have to use previous parts in........
    i hope there is or i will get a zero
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    (Original post by Don Pedro K.)
    Guys just a last minute panic check; if moving parallel to i, the j component = 0 and vice versa right??

    And if north-west then??
    -i+j
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    (Original post by Alevelhelp97)
    -i+j
    -i+j=0 ??
    then can you rearrange to get j=i

    thanks
 
 
 
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