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    What did people get for the impulse question? I've heard a rather large variety of answers, I got 3Ns iirc but it was definitely a hard question so just wondered
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    Did anyone else find the exam extremely hard compared to past papers? i couldnt do a single question.
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    (Original post by hogree)
    Cheers matey should be it. Just the R part of 2 I'm skeptical. The question asked the Force of the Brick on the Pan. So surely that would be the weight of the Brick, not the Reaction?

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    For the force on the pan, i did 15.45-1.5g, which is the bricks weight. So i got 0.75N.

    But i wrote that the reaction force is 15.45N.
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    (Original post by Reda2)
    Thank you for this beautiful answer, I can sleep well tonight then, but omg I was so worried when I found out.
    This is the video:
    https://www.youtube.com/watch?v=2_ruJ5i8ZJ4

    The bit about illegible scripts is at 7:00
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    (Original post by dodgewc25)
    Anyone know how many marks the moments question was?
    7. How did you do this. I got something like M(RT): (4 - d)30g + 4MG = 0 and did the same for other but couldnt get it to work?
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    can someone explain question 2b ?
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    Please could someone post the rough questions!
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    and question 7a the force vector one
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    Anyone know marks for each question?
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    (Original post by Jellymath)
    Fairly easy test this time around. Here are my answers which should be correct:

    1. 104 degrees, 640i+640j
    2. T=20.6N , R=15.5N
    3. Impulse = 3Ns
    4. Graph with one point of intersection, T = 8.75s
    5. Moments qn: d=1.2m M=42kg
    6. Coefficient of friction = 0.727
    7. 2.5i+2.5j, 13 ms-1
    8. T=11.8N, F=16.6N bearing 225 degrees
    Why did you put your last answer as a bearing?
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    (Original post by carrm123)
    How many marks was the impulse question worth?
    7 marks
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    Sorry but the answer is definitely 15.5N. It is calculated by using F=ma on the brick where F = R-1.5g. Then, using Newton's third law, this is equal in magnitude to the force exerted on the pan by the brick

    As for my last answer, I only wrote this for convenience. I drew a diagram and wrote 45 degrees to the downward vertical. This is equivalent to 225 degrees bearing
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    (Original post by ChilliLemon)
    For the force on the pan, i did 15.45-1.5g, which is the bricks weight. So i got 0.75N.

    But i wrote that the reaction force is 15.45N.
    But that's not the force of the Brick on the Pan.... that's the Resultant Force. The Pan on the Brick is 15.45 and the Brick on the Pan is 14.7. So surely the answer is 14.7. Am I missing something?

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    If i get a 0 on m1 what would i need in c1-c4 and s1 to get a c or above overall
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    Wth I got 3.2Ns for the Impulse Q?
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    (Original post by DanB33)
    I got the same as you. I did the question 3 times and got the same answer each time so...
    Please god be right!
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    To find the resultant force on the pulley do you do 2 tcos45
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    (Original post by gunners98)
    It was worth 7 marks I think. You'll probably get 1 for frictional force after rebound, 2 for working out acceleration with f=ma, 1 for working out speed that it rebounded (suvat), and 2 for the method of calculating the impulse, and 1 for the answer. Not sure though
    (Original post by Mwo)
    If you got 0.2 on the Impulse question, like me, then we were wrong.

    0.2 is the answer you get when you calculate the Impulse but forget to make the velocity (4) negative.

    The mass of the particle was 0.4g and the velocity AFTER it hit the wall that you worked out was 7/2 (which should get method marks if you got that answer)

    So then the Impulse was

    I = 0.4(-3.5) - 0.4(4) = -3Ns
    NOT
    I= 0.4(3.5) - 0.4(4) = -0.2Ns

    We will get some method marks though.
    Cheers absolute legends. How many marks for 0.2 you think?
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    Q1a) 104 degrees
    Coefficient of friction question 0.727(well at least 0.7 something)
    F2-2.5i,2.5j
    Impulse- 3Ns
    That's all I can remember
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    (Original post by Humiliation)
    How do you get 15.5 for the pan question part b?

    Do you look at the pan alone, or the brick alone?

    I did weight of lift + R (reaction of brick going down) - T = mass of lift x acceleration.

    Is that right? Or is it 0.5g - R = 0.5a
    use the brick alone:
    weight of brick - R of brick = mass of brick x a
 
 
 
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