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    (Original post by megans98)
    Begging for someone to do some worked solutions with rough qs like there was for C2!!
    Give them chance it's not even midday
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    should we make a new thread for a mark scheme?
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    I think i may of accidentally used 0.5 as the mass for the accleration for 2b instead of 1.5
    The equation i showed and everything else was right would i get a method mark?
    I put R=1.5g +0.5*0.5*
    when R=1.5g +1.5*0.5*

    And i put southwest as the direction>
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    Question 3 for anyone who didn't know:

    R(->) F = 0.4a => R/8 = 0.4a, where R = 0.4g.

    So, a = g/8 ms^-2

    Then we must find the speed immediately after impact:
    s=5 , u=?, v=0, a=-g/8 (<- +)
    So you get: 0=u^2 - 12.25 => u=7/2 ms^-1

    I = m(v-u) => I = 0.4(3.5-(-4) = 3 Ns.
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    What did anyone get for question 1 (vectors)?
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    (Original post by stephencurtis)
    I accidentally did one of the questions in pencil :/, marks or no?
    Probably.

    If the question doesn't scan properly then it is marked by hand / with the paper copy of your answers. Pencil should scan anyway - e.g. for the graph question on the paper. Unless there's a fault in the system or your examiner (i.e. unless Edexcel screw up), the question should be marked just the same as it would if you'd written in pen.
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    Hey guys, how did everyone find it?

    The vector question on 7 was a tricky one!

    I got 5(route2)/2 for it which was something like 3.54 rounded (7 mark question)

    Also what did you guys get for the force exerted on the scale pan by the brick? I used R - 0.5g = 0.5a and got something like 5.15N because it said on the scale pan by the brick, in previous exams it said on the woman by the lift and used the womans mass so i hope the same applied here! At first I said R - 1.5g = 1.5a but I remembered the past exam questions

    Last thing i found a bit tricky was the direction on the very last question. I said it acted downwards, anyone else say the same? (for 2Tcos45)
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    How many marks was q1 worth?
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    (Original post by KINGYusuf)
    How did people get 3Ns for the Impulse??

    I = mv - mu

    I = (0.4)(4)-(0.4)(-4) = 3.2Ns

    Idk
    7 Marks, you really think itll be that easy aha, basically you have to take into account the friction which your method doesnt.

    it was 3Ns
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    (Original post by Jackhawkins21)
    speed coming back out for 3.5


    I used conservation of momentum and got 4 m/s backwards, damnit I'm so dumb haha
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    What was question 7b asking for ??
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    Me too
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    (Original post by ChilliLemon)
    The answer is not 14.7 because the brick is accelerating, so the force is 15.45N
    Still don't get how that would be the answer to the specific question. It said the force of the Brick on the Pan, not the Pan on the Brick.

    Posted from TSR Mobile
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    somehow for d i got d=1.6
    and for M i got M=66
    can someone help why cause my working was correct
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    guys if you know the answers to the question post them here:

    http://www.thestudentroom.co.uk/show...5#post65556385
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    (Original post by KINGYusuf)
    How did people get 3Ns for the Impulse??

    I = mv - mu

    I = (0.4)(4)-(0.4)(-4) = 3.2Ns

    Idk

    It was I = M(V - U)
    M was 0.4, V = +/-3.5 and U = -/+4 (depending on which direction you defined as positive)

    I = 0.4 (3.5 - -4) or 0.4 (-3.5 - 4)
    = 0.4 * 7.5 or 0.4 * -7.5
    = 3 Ns
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    (Original post by unimaginable118)
    Does anyone remember what they did for the pan question?
    for part a) I used T- particle x g = particles x a
    I forgot what i got as an answer though:\
    basically I used the values for the whole system instead of just one particle.
    Is that right???

    the weights of the pan and the brick were 0.5g and 1.5g. the acceleration was o.5 I think
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    Posted from TSR Mobile

    I'm pretty sure you used the incorrect length when taking the forces around T. Did you by any chance multiple 30g by (6-d)
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    I wrote 5(Route 2)/5 N for 7(a) without using i or j, how many marks would i get for that? (which is the route of 2.5squared + 2.5squared)

    Also for the force exerted on the scale pan i used R - 0.5g = 0.5a and got 5.15N If this is wrong how many marks would I lose?
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    (Original post by theviki)
    I got d=1.2 m and M = 42 kg
    I got that too, did anyone else?
 
 
 
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