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    What was the first question, does anyone remember ?
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    Does anyone know how many marks 3, 7a and 8b were worth?
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    (Original post by Don Pedro K.)
    Guys, for the magnitude of the force exerted on pan by brick, I got the right answer but I did it in a way which gave a negative answer for R. how many marks do you think I would lose?
    Maybe 1?
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    (Original post by Don Pedro K.)
    Guys, for the magnitude of the force exerted on pan by brick, I got the right answer but I did it in a way which gave a negative answer for R. how many marks do you think I would lose?
    7 marks
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    (Original post by thestarter)
    can someone explain the Vectors F2 question please?
    The force F1 was given to you and said F2 was in the diretion of (i + j) i believe.Also it said the resultant of the two (adding them up) was in the direction of (i + 3j).
    'in the direction of' just means that vector is some multiple of the one they gave you. So in order to solve this problem, you had to equate F2 to a multiple of (i + j)
    So F2= k(i + J)
    Same goes for the resultant so

    F1 + F2 (which we just recognised as k(i + j)) = L(i + 3j)
    Where L is just another constant representing a multiple of hence 'in direction of'

    Phew so then we multiple everything out and equate all the i components and j components to form 2 simultaneous equation
    From where you calculate the constant K for example in this case and multiple by it the vector they gave you (direction of) and so you get 2.5
    hope that helped
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    (Original post by igot100ums)
    how were you meant to do 7a
    This is how I did 7(a):

    Set up a pair of simultaneous equations by multiplying the vectors we were given as parallel by some constant.

    So:
    F1+F2=R => ( - i + j ) + k( i + j ) = λ( i + 3j ) I can't remember the vectors given exactly, this is what I think.

    Then equate i components: -1 + k = λ
    Then equate j components: 1 + k = 3λ and solve for k. => k = 5/2

    (Original post by NatoHeadshot)
    Quick question hoping someone can clear this out
    1) for the first question I got got 14 soemthjng degrees and I mentioned this is from the positive X AXIS or to the right
    People seem to have done 90+ this to get from y axis but they didn't mention so I just used X axis

    2) for the coefficient of friction I got the right answer but it came out negative because I took the friction pointing UP the slope and someone said it was down the slope
    How much would I lose out I think it was 10 marks ?
    1) I'm not sure if it said as a bearing. If it said as a bearing you needed 104 degrees. Likewise if it said from the j direction.

    2) You'd probably lose one mark if you left is as a negative. You would probably lose no marks if you wrote afterwards something like: "negative as friction is acting down the slope", though the question did say that it was on the point of slipping up the plane - so I'm not sure.
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    (Original post by ODES_PDES)
    Maybe 1?
    that'd be alright hahaha
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    (Original post by KhanHarbs)
    What was the first question, does anyone remember ?
    Bearing of the value of 104

    sadly read the i and j components the wrong way around :'(
    silly mistake
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    lose a mark for Ns-1 rather than Ns?
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    For the moments question I dot d = 1.6m and M = 66kg. Please could somone explain why this is incorrect?
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    What do people estimate the raw marks needed to get 90 or 100 UMS
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    Hey. What if i didn't give an answer but attempted to work it out. Would i gain method marks if i was leading towards the right path?
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    (Original post by Don Pedro K.)
    KloppOClock hogree Guys for the F2 vectors question, I realised at the last minute how to do it so I had to rush it. I got the two sets of simultaneous equations, but then solved them wrongly. How many marks out of 7 do you reckon I'll get? 4?
    7 marks
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    (Original post by the___jackal)
    lose a mark for Ns-1 rather Ns?
    perhaps, sometimes they dont care about units but other times they do
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    Is M exactly 42, I got 42,6?
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    (Original post by Hasib98)
    Bearing of the value of 104

    sadly read the i and j components the wrong way around :'(
    silly mistake
    I meant the question not the answer, I have a feeling I read it wrong..
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    What do people think that the raw marks needed to get 90 or 100 UMS??
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    i used the triangle method and ended up getting a magnitude for the force f2, i did this using the sine rule, would the get any of the 7 marks
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    (Original post by KhanHarbs)
    I meant the question not the answer, I have a feeling I read it wrong..
    Bearing at which Q is travelling i believe
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    how are people getting 3Ns for impulse? i got 2.48 or something and it seems to work using kinematics,not sure how people are getting 3.5m/s for the velocity off the wall?
 
 
 
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