Edexcel AS/A2 Mathematics M1 - 8th June 2016 - Official Thread

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2014 a was 58 and full ums was like 70... Hopefully something like that

I'm beginning to think the only answer they'll accept for the last question is 225 as a bearing.

Saying 45 doesn't make sense. It's not specific enough. Your force could be going south east or south west.

Only giving your answer as a bearing leaves no uncertainty to the examiner

Reply 1522

Shireenyousaf123

I wrote m=0.73 to 2sf will I still get the mark and for the bearing I wrote 135 from i/x axis and I wrote 45 degrees below x drew diagram aswell. Do you get penalised for not writing units I wrote M=42 is this right

Reply 1523

ponchepower

Original post by biubiubiu

My m1 was a disaster. I should've revised. I might get 60, so a B or even C?

lol

Reply 1524

username963570

How many marks was the last question (Q8) worth in total?

Reply 1525

CaiusMartius

Original post by lucabrasi98

in 2013 you got the mark for drawing a diagram and showing the force at an angle of 45 so i guess it'll be like that again i guess

Reply 1526

Tom22561

Can some one remember what question 2 was especially the working out for 2b?

Reply 1527

username963570

Original post by CaiusMartius

in 2013 you got the mark for drawing a diagram and showing the force at an angle of 45 so i guess it'll be like that again i guess

How many marks was the last question worth again? :/

Reply 1528

Azzer11

Original post by SirRaza97

Alot of people are saying 59-60 for A but keep in mind it was an IAL paper (i think. It looked like it from the front) and last IAL papers were about 53-54 for A

What are you talking about? It wasn't an IAL paper...

Posted from TSR Mobile

Reply 1529

CaiusMartius

Original post by Fas

How many marks was the last question worth again? :/

4, 3 marks for like some pythagoras stuff and another mark for showing the direction. Reckon either you show it on a diagram or you have a bearing, i agree just saying 45 degrees from the horizontal isn't specific enough (although it should be fine with a diagram).

Reply 1530

Ppatel0

Original post by Tom22561

Can some one remember what question 2 was especially the working out for 2b?

It was the scale and the mass. Can't remember fully but you had to use equations of motion

Reply 1531

username963570

Original post by CaiusMartius

Ah ok, that was the pulley question wasn't it? Just trying to get it all straight in my head

Reply 1532

Styster99

Original post by Tom22561

Can some one remember what question 2 was especially the working out for 2b?

Question 2 was the one about the scale-pan with a brick in it

2a) Considering the whole system:

T - 2g = 2a
T = 2g + 2a
T = 2(9.8) + 2(0.5)
T = 20.6N

b) Considering the brick:

R - 1.5g = 1.5a
R = 1.5g + 1.5a
R = 1.5(9.8) + 1.5(0.5)
R = 15.45N

Reply 1533

123chem

Original post by CaiusMartius

Oh, i didnt read that part, and just read magnitude. So, i didnt give dirention, but i did draw a diagrap with 45 degree angle, and the reaction at it as well, will that be enough? (i doubt it)

Also, i guess most of us got physics tomorrow? aqa here

Reply 1534

CaiusMartius

Original post by Fas

Ah ok, that was the pulley question wasn't it? Just trying to get it all straight in my head

yup, dw about it too much, im sure you did fine it's in the past

Reply 1535

lucabrasi98

Original post by Azzer11

What are you talking about? It wasn't an IAL paper...

Posted from TSR Mobile

What even is an IAL paper? The international papers?

Original post by CaiusMartius

in 2013 you got the mark for drawing a diagram and showing the force at an angle of 45 so i guess it'll be like that again i guess

Oh i guess that'd be fine. Although oads of people in my class literally just wrote 45 degrees from the horizontal then laughed cause I was the only one who got a bearing.

I initially accepted that i was wrong but upon giving it further thought, I think they messed up.

Reply 1536

Med3

For F2: is it 2.5i + 2.5j

Reply 1537

SirRaza97

Original post by Azzer11

What are you talking about? It wasn't an IAL paper...

Posted from TSR Mobile

I thought it was because the front cover looked like this (from previous IAL paper):

A standard paper looks like this:

I mean I could be wrong of course. That's my reasoning.

1.PNG85.6KB

Reply 1538

username2378153

Original post by thestarter

how many marks do you reckon ill get?
....
7. a. -1+k=z and 1+k=3z and sub z=-1+k into 1+k=3z so 1+k=3(-1+k) which gives k=0.5 so F2 = 0.5i + 0.5j - if this is wrong then how many marks?
b. V = 12i +5j, thus speed = 13 ms-1

8. a. Tension = 11.76 = 12N (2sf)
b. RF = √(11.76)^2 + (11.76)^2 = 16.6 = 17N (2sf) with a bearing of 045

I don't remember the paper that well but I think this is what I got

F_1=-i+2j

and let

F_2=\lambda (i+j)

then

F_{resultant} = F_1+F_2= (-1+\lambda)i+(2+\lambda)j

since we know that the resultant force is in the direction of

i+3j

3(-1+\lambda)=(2+\lambda)[br]\Rightarrow \lambda =2.5[br]\Rightarrow F_2=2.5i+2.5j[br]\Rightarrow F_{resultant}=1.5(i+3j)

Also for the last question it asked for the direction of the force exerted on the pulley. So if your taking the pulley as the origin and the north being upwards perpendicular to the table, then the bearing would be 225. But if you drew the diagram with arrows and angles, you'll probably still get it. Your other answers look familiar but I can't really say a mark with certainty - maybe mid 60s depending on that moments q.