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    (Original post by Tas0920)
    does anybody know how many marks the moments question was altogether?
    7 marks altogether
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    (Original post by SirRaza97)
    7b told you the acceleration and the velocity of P at t=0. Can't remember the values. Acceleration is rate of change of velocity or in other words delta v/delta t = a. So you find delta v byt multiplying the acc. by 3 (3 = delta t). That value is the amount the velocity of P changed by from t=0 to t=3. So you add the starting velocity and the change in velocity. That gives you the velocity at t=3. Then you use pythagoras to find the speed and there you have it. Hope that makes sense.
    I used V = u + at to work out the Velocity at t=3. Then used pythagoras to work out speed.

    Does that sound okay?
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    (Original post by Tas0920)
    does anybody know how many marks the moments question was altogether?
    7 i think
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    Hi Guys does anyone have an unofficial mark scheme for the M1 today?
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    I love how they bombarded with quite hard questions and then made the last question so easy hahaha
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    (Original post by rindog3000)
    7 marks altogether
    thanks
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    (Original post by pereira325)
    7 i think
    thanks
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    Hey guys so basically, on the moments question, I got two sets of correct simultaneous equations. However, I then, instead of subtracting them, I added them together (thinking I was substracting so one of the variables still cancelled out). This caused me to get a wrong value for M and hence also a wrong value for d.

    How many marks out of 7 do you think I would get?

    hogree KloppOClock
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    can anyone remember and can tell me what the diagram in Q8 looks like???
    Also, for Q4, for the graph, I drew the line for Train N under the line Train M but I got the correct answer for part b, would I still get the 4 marks for it as T was unknown in part a so I thought it doesnt matter...
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    Wait guys isn't the ans for 8b (the last Q) 8. something as it's 2Tcos45? How did people get 16.6N?
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    (Original post by Don Pedro K.)
    Hey guys so basically, on the moments question, I got two sets of correct simultaneous equations. However, I then, instead of subtracting them, I added them together (thinking I was substracting so one of the variables still cancelled out). This caused me to get a wrong value for M and hence also a wrong value for d.

    How many marks out of 7 do you think I would get?

    hogree KloppOClock
    So its 7 marks, here is how I think the marks could be broken down.

    2 marks for each moment equation
    1 mark for simultaneously solving
    1 mark for correct answer

    1 mark for subbing d into equation with m
    1 mark for correct answer of d
    and there would be a third mark in this part somewhere?
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    how many marks was each question worth?
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    (Original post by SirRaza97)
    I dont think so. 11.76 is the exact answer so I would be suprised if you did. Lilkely will have an AWRT (Anything which rounds to 11.8)
    If g is involved in the question then you have to round to 3sf or 2sf (as is stated in the instructions on the front of the paper) so it won't be awrt - you can lose up to 1 mark for this per question
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    (Original post by tsingb)
    can anyone remember and can tell me what the diagram in Q8 looks like???
    Also, for Q4, for the graph, I drew the line for Train N under the line Train M but I got the correct answer for part b, would I still get the 4 marks for it as T was unknown in part a so I thought it doesnt matter...
    For question 4 the areas have to be the same because the area is the distance and they both traveled 975m (I think?) so the N has to be above M. Normally you get a mark for the shape of the graph and where one crosses the other twice so at most you'd probably lose 2 marks
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    (Original post by KINGYusuf)
    Wait guys isn't the ans for 8b (the last Q) 8. something as it's 2Tcos45? How did people get 16.6N?

    2*11.76*cos45=16.6

    you are right that its 2tcos45, did you have the correct value of T?
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    Are you sure that for question 5, μ was to 2 significant figures and that 8b asked for the angle?
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    (Original post by KloppOClock)
    So its 7 marks, here is how I think the marks could be broken down.

    2 marks for each moment equation
    1 mark for simultaneously solving
    1 mark for correct answer

    1 mark for subbing d into equation with m
    1 mark for correct answer of d
    and there would be a third mark in this part somewhere?
    In the May 2013 mark scheme:

    Name:  Capture.JPG
Views: 313
Size:  38.1 KB
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    does anybody remember the wording of the scale pan question part b? thanks
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    (Original post by Person18)
    I did the same thing! I'm glad it's not just me. D = 2.25m as well right?

    I don't understand either, I did the whole simultaneous thing
    yep 2.25 I think we we at least get most of the method marks
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    (Original post by Don Pedro K.)
    In the May 2013 mark scheme:

    Name:  Capture.JPG
Views: 313
Size:  38.1 KB
    Was the May 2013 also worth 7 marks? I also did the same thing as you, and I'm hoping for atleast 3 marks if not 4.
 
 
 
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