whyis the modulus of 1 + itan(x) where 1/2 pi<x<pi -x whereas the same complex number between 0 and 1/2 pi has a modulus of x?
Modulus and argument of complex numbers in polar form Watch
- Thread Starter
- 24-02-2016 21:14
- 24-02-2016 22:32
I don't think you have quoted the question very well at all but I am guessing that the reason s that the tan of angles between 90 and 180 is negative whereas it is positive up to 90.
I.e. You are talking about the argument of complex number