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    I am disgusted today with this question ... I have spent then last 10 hours on it and I am about to pull my hair out as I do not even know what topics it involves ...





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    http://www.thestudentroom.co.uk/show...5&postcount=91
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    \text{sheep } \leq L \leq \text{ candle}

    Where L is the length of the spring.
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    (Original post by 16Characters....)
    \text{sheep } \leq L \leq \text{ candle}

    Where L is the length of the spring.
    :rofl: I'm dying. This is brilliant. :lol:
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    (Original post by Zacken)
    :rofl: I'm dying. This is brilliant. :lol:
    The joke's on me, \text{sheep} > \text{candle}. I hadn't actually thought of that before sending.
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    (Original post by 16Characters....)
    The joke's on me, \text{sheep} \geq \text{candle}. I hadn't actually thought of that before sending.
    Ah, yes - you can't solve nonsensical Facebook questions, you must be utterly horrid at mathematics.
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    (Original post by 16Characters....)
    \text{sheep } \leq L \leq \text{ candle}

    Where L is the length of the spring.
    omg... :rofl2:
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    I don't get it.
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    94 views and nothing sensible ...
    this question begins to annoy me ...
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    any hints?
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    (Original post by TeeEm)
    any hints?
    Will give it a rip when I'm home. Energy the way to go?
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    (Original post by aymanzayedmannan)
    Will give it a rip when I'm home. Energy the way to go?
    Energies only if you can handle Lagrangian/Hamiltonian Mechanics ...
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    who is the top dog in mechanics in Forum 38?
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    Could you assume that you get a right angled triangle for the actual length of the spring, with x being the displacement of the particle?

    So the hypotenuse is sqrt(x+l)?

    Or maybe it is just normal shm with the acceleration having a cosine component and the displacement having a sin component?
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    (Original post by TheBBQ)
    Could you assume that you get a right angled triangle for the actual length of the spring, with x being the displacement of the particle?

    So the hypotenuse is sqrt(x+l)?

    Or maybe it is just normal shm with the acceleration having a cosine component and the displacement having a sin component?
    a very hairy problem ...
    a lot harder than it looks ...
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    (Original post by TeeEm)
    a very hairy problem ...
    a lot harder than it looks ...
    I'll have a crack at it on my train home tonight. Do you have a set of numerical answers? And this must be A-level standard right?
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    (Original post by TheBBQ)
    I'll have a crack at it on my train home tonight. Do you have a set of numerical answers? And this must be A-level standard right?
    A level knowledge still (AQAers have an advantage)
    Answer 1<=length <=3
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    (Original post by TeeEm)
    a very hairy problem ...
    a lot harder than it looks ...
    Well that's brilliant because already it looks impossible

    :emo:
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    (Original post by Student403)
    Well that's brilliant because already it looks impossible

    :emo:
    I know right... :emo:
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    (Original post by TeeEm)
    A level knowledge still (AQAers have an advantage)
    Answer 1<=length <=3
    Are we talking about M2-M3 knowledge?
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    (Original post by Marxist)
    Are we talking about M2-M3 knowledge?
    depends on the board ....
 
 
 
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