I am disgusted today

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TeeEm
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#1
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#1
I am disgusted today with this question ... I have spent then last 10 hours on it and I am about to pull my hair out as I do not even know what topics it involves ...





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http://www.thestudentroom.co.uk/show...5&postcount=91
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16Characters....
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#2
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#2
\text{sheep } \leq L \leq \text{ candle}

Where L is the length of the spring.
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Zacken
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#3
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#3
(Original post by 16Characters....)
\text{sheep } \leq L \leq \text{ candle}

Where L is the length of the spring.
:rofl: I'm dying. This is brilliant. :lol:
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16Characters....
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#4
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#4
(Original post by Zacken)
:rofl: I'm dying. This is brilliant. :lol:
The joke's on me, \text{sheep} > \text{candle}. I hadn't actually thought of that before sending.
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Zacken
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#5
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#5
(Original post by 16Characters....)
The joke's on me, \text{sheep} \geq \text{candle}. I hadn't actually thought of that before sending.
Ah, yes - you can't solve nonsensical Facebook questions, you must be utterly horrid at mathematics.
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Marxist
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#6
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#6
(Original post by 16Characters....)
\text{sheep } \leq L \leq \text{ candle}

Where L is the length of the spring.
omg... :rofl2:
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Ladymusiclover
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#7
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#7
I don't get it.
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TeeEm
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#8
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#8
94 views and nothing sensible ...
this question begins to annoy me ...
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TeeEm
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#9
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#9
any hints?
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Ayman!
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#10
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#10
(Original post by TeeEm)
any hints?
Will give it a rip when I'm home. Energy the way to go?
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TeeEm
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#11
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#11
(Original post by aymanzayedmannan)
Will give it a rip when I'm home. Energy the way to go?
Energies only if you can handle Lagrangian/Hamiltonian Mechanics ...
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TeeEm
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#12
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#12
who is the top dog in mechanics in Forum 38?
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TheBBQ
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#13
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#13
Could you assume that you get a right angled triangle for the actual length of the spring, with x being the displacement of the particle?

So the hypotenuse is sqrt(x+l)?

Or maybe it is just normal shm with the acceleration having a cosine component and the displacement having a sin component?
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TeeEm
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#14
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#14
(Original post by TheBBQ)
Could you assume that you get a right angled triangle for the actual length of the spring, with x being the displacement of the particle?

So the hypotenuse is sqrt(x+l)?

Or maybe it is just normal shm with the acceleration having a cosine component and the displacement having a sin component?
a very hairy problem ...
a lot harder than it looks ...
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TheBBQ
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#15
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#15
(Original post by TeeEm)
a very hairy problem ...
a lot harder than it looks ...
I'll have a crack at it on my train home tonight. Do you have a set of numerical answers? And this must be A-level standard right?
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TeeEm
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#16
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#16
(Original post by TheBBQ)
I'll have a crack at it on my train home tonight. Do you have a set of numerical answers? And this must be A-level standard right?
A level knowledge still (AQAers have an advantage)
Answer 1<=length <=3
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Student403
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#17
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#17
(Original post by TeeEm)
a very hairy problem ...
a lot harder than it looks ...
Well that's brilliant because already it looks impossible

:emo:
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Zacken
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#18
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#18
(Original post by Student403)
Well that's brilliant because already it looks impossible

:emo:
I know right... :emo:
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Marxist
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#19
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#19
(Original post by TeeEm)
A level knowledge still (AQAers have an advantage)
Answer 1<=length <=3
Are we talking about M2-M3 knowledge?
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TeeEm
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#20
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#20
(Original post by Marxist)
Are we talking about M2-M3 knowledge?
depends on the board ....
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