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# Differentiate watch

1. r = tan T/6 + 4 cos T with respect to T

Would this be dr/dt = sec^2 T/6 - 4 sin T ?

Any help appreciated
2. almost... when you differentiate tan (at) you get a{sec2at}
3. (Original post by ak992)
r = tan T/6 + 4 cos T with respect to T

Would this be dr/dt = sec^2 T/6 - 4 sin T ?

Any help appreciated
http://www.thestudentroom.co.uk/forumdisplay.php?f=38
4. (Original post by the bear)
almost... when you differentiate tan (at) you get a{sec2at}

So it would be dr/dT = 1/6 sec^2 T -4 sin T ?
5. (Original post by ak992)
So it would be dr/dT = 1/6 sec^2 T -4 sin T ?

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Updated: February 26, 2016
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