AQA Physics PHYA4 - 20th June 2016 [Exam Discussion Thread] Watch

philo-jitsu
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(Original post by Billsonbubbles)
Sorry to keep Posting on peoples comments advocating my videos,


But I do some past paper tutorials for the multiple choice questions explaining why each option is chosen etc... and going through each option which does mean of course the videos are fairly long, but do have a look



bills7187 on youtube



Cheers,

Will
Will take a look after i get biol4 done with today

Cheers
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Alby1234
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Can anyone explain how the answer to this is A? Name:  Physics capture 3.JPG
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Billsonbubbles
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(Original post by ¡Muy bien!)
Hi,
Where can I get these from?
Thanks
Hi ,



I dont have a website to put them on,so I can just email you them instead?


If you put your email on here on inbox me with it I can send it to you.



Just let me know which ones you want .... I.e Mutliple choice, normal unit 4, unit 5 - nuclear and thermal, astrophysics


However I just had a look and I need to make a few changes to some of the questions.

Cheers,

Will
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nyxxllis
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(Original post by Alby1234)
Can anyone explain how the answer to this is A? Name:  Physics capture 3.JPG
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Name:  IMG_20160616_114549.jpg
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Rearrange charge over mass to find an equation for charge, equate the electrostatic force (F=EQ) to the weight of the ion (F=mg), the value for mass will cancel and you can rearrange for E.
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nyxxllis
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(Original post by Billsonbubbles)
Hi ,



I dont have a website to put them on,so I can just email you them instead?


If you put your email on here on inbox me with it I can send it to you.



Just let me know which ones you want .... I.e Mutliple choice, normal unit 4, unit 5 - nuclear and thermal, astrophysics


However I just had a look and I need to make a few changes to some of the questions.

Cheers,

Will
Would it be possible for me to get some of these questions too? Would be so helpful.
Thanks in advance.
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ryandaniels2015
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Hi Will,
Would love to also have access to these questions. Thanks

(Original post by Billsonbubbles)
Hi ,



I dont have a website to put them on,so I can just email you them instead?


If you put your email on here on inbox me with it I can send it to you.



Just let me know which ones you want .... I.e Mutliple choice, normal unit 4, unit 5 - nuclear and thermal, astrophysics


However I just had a look and I need to make a few changes to some of the questions.

Cheers,

Will
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Billsonbubbles
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(Original post by nyxxllis)
Would it be possible for me to get some of these questions too? Would be so helpful.
Thanks in advance.
Yeah no worries,


When I have made the changes I will post my email on here , and you can just email me so I have your email so i can email you bacl



Also if anyone is doing D1 I have an exam I created for that as well;



Cheers,


Will
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pleasehelp1
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any one got the answers for past paper questions from the text book
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MintyMilk
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http://prntscr.com/bh5de6

I thought the whole thing about these questions was that you have to switch whatever direction of current you're given to the opposite to get conventional current?

Have they always used simply "current" in questions to mean conventional current by default?
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rory58824
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(Original post by MintyMilk)
http://prntscr.com/bh5de6

I thought the whole thing about these questions was that you have to switch whatever direction of current you're given to the opposite to get conventional current?

Have they always used simply "current" in questions to mean conventional current by default?
Yes they have, I think the textbook shows this in the first few pages of this topic. If electrons are fired perpendicular then you take the conventional current direction.
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MintyMilk
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(Original post by rory58824)
Yes they have, I think the textbook shows this in the first few pages of this topic. If electrons are fired perpendicular then you take the conventional current direction.
That's my point, you surely switch the current direction to get conventional current, which means that the force is acting upwards. They've given the direction of current in the question, not conventional current. They surely can't mean conventional current by referring simply to current, otherwise that would mess up any question that refers to current in general
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rory58824
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(Original post by MintyMilk)
That's my point, you surely switch the current direction to get conventional current, which means that the force is acting upwards. They've given the direction of current in the question, not conventional current. They surely can't mean conventional current by referring simply to current, otherwise that would mess up any question that refers to current in general
I know what you mean, but I've followed what I've said above and that has always worked.
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MintyMilk
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http://prntscr.com/bh5tk2

note: June 14, answer is 0.8

Surely at the minimum at 0.2 seconds (assuming they mean that this represents the equilibrium point), some of the kinetic energy will have already been transferred to gravitational potential just by virtue of the fact that the mass has moved vertically up from its starting point, i.e. why does the graph display no potential energy when it must clearly have some potential energy?
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particlestudent
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(Original post by MintyMilk)
http://prntscr.com/bh5tk2

note: June 14, answer is 0.8

Surely at the minimum at 0.2 seconds (assuming they mean that this represents the equilibrium point), some of the kinetic energy will have already been transferred to gravitational potential just by virtue of the fact that the mass has moved vertically up from its starting point, i.e. why does the graph display no potential energy when it must clearly have some potential energy?
Doesn't it have a maximum gravitational potential when it's at the top and maximum elastic potential at the bottom? I may be entirely wrong here but I think in the middle those two cancel out?

I'm probably wrong :/
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philo-jitsu
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(Original post by MintyMilk)
http://prntscr.com/bh5tk2

note: June 14, answer is 0.8

Surely at the minimum at 0.2 seconds (assuming they mean that this represents the equilibrium point), some of the kinetic energy will have already been transferred to gravitational potential just by virtue of the fact that the mass has moved vertically up from its starting point, i.e. why does the graph display no potential energy when it must clearly have some potential energy?
I think in these questions it classes grav potential energy at zero when its at equlibrium, otherwise how high you are when you do the experiment would affect it.... i think this i just another case of having to simplify data for a level spec....unless i completely misunderstood you

It would make these questions much more difficult, as the only time kinetic energy is actually gained would be when it oscillates from highest point to equilibrium.
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philo-jitsu
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Technically i dont think any kinetic energy would actually be gained moving from lowest displacement to equilibrium, the elastic potential would be directly converted to gpe
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xMillnsy
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How do you do this? Name:  2016-06-16.png
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MintyMilk
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(Original post by philo-jitsu)
I think in these questions it classes grav potential energy at zero when its at equlibrium, otherwise how high you are when you do the experiment would affect it....
yeah, I think that fixes my problem with it, thanks. Though the question does still seem pretty nebulous to me
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philo-jitsu
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(Original post by xMillnsy)
How do you do this? Name:  2016-06-16.png
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Is it c?

And these questions are tough....seen the same style come up before..

I think its 1.95 over diff in times equals 39

Because 39 oscilations times 1.95 and 39 times 1.9 the diff between total times is 1.95....soooo they will be at the same point but the 1.9 oscilator will be 1 whole oscilation ahead...but still in phase....its harder to word than i though :-/
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philo-jitsu
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(Original post by MintyMilk)
yeah, I think that fixes my problem with it, thanks. Though the question does still seem pretty nebulous to me
Yeah some questions are a bit odd....your lucky you dont do biology....its not that some of the answers are vague its that they are out right wrong ......its infuriating!

Its why i like maths....maths is safe :-)
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